extreme f(x)=x(17-2x)(50/2-x)

Lösung

extrempunkte

f (x) = x (17 - 2 x) (\frac{50}{2} - x)

Maximum (\frac{67 - 1939}{6}, \frac{1939 1939 - 44488}{54}), Minimum (\frac{67 + 1939}{6}, - \frac{44488 + 1939 1939}{54})

Schritte zur Lösung

f^{'} (x) = 6 x^{2} - 134 x + 425

Intervalle finden:

Ansteigend

: - \infty < x < \frac{- 1939 + 67}{6},

Absteigend

: \frac{- 1939 + 67}{6} < x < \frac{1939 + 67}{6},

Ansteigend

: \frac{1939 + 67}{6} < x < \infty

Stecke

x = \frac{67 - 1939}{6}

x (17 - 2 x) (\frac{50}{2} - x) : \frac{1939 1939 - 44488}{54}

Maximum (\frac{67 - 1939}{6}, \frac{1939 1939 - 44488}{54})

Stecke

x = \frac{67 + 1939}{6}

x (17 - 2 x) (\frac{50}{2} - x) : - \frac{44488 + 1939 1939}{54}

Minimum (\frac{67 + 1939}{6}, - \frac{44488 + 1939 1939}{54})

Maximum (\frac{67 - 1939}{6}, \frac{1939 1939 - 44488}{54}), Minimum (\frac{67 + 1939}{6}, - \frac{44488 + 1939 1939}{54})

e x t re m e f (x, y) = 9 y^{2} - 3 x^{2} - 10 y + 5 x y

e x t re m e f (x) = x^{3} - 5 x^{2} + 3 x + 12, (- 2, 4)

e x t re m e f (x) = ln (x y - 6)

e x t re m e f (x) = e^{4 x} + e^{- x}

e x t re m e y = \frac{- 3 x}{x ^{2} + 2}