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Beliebt Geometry >

2x^2+2y^2+4x+8y=1

Lösung

2 x^{2} + 2 y^{2} + 4 x + 8 y = 1

Lösung

(a, b) = (- 1, - 2), r = \frac{11}{2}

Schritte zur Lösung

2 x^{2} + 2 y^{2} + 4 x + 8 y = 1

Rewrite

2 x^{2} + 2 y^{2} + 4 x + 8 y = 1

in the form of the standard circle equation

(x - (- 1))^{2} + (y - (- 2))^{2} = (\frac{11}{2})^{2}

Therefore the circle properties are:

(a, b) = (- 1, - 2), r = \frac{11}{2}

Graph

Beliebte Beispiele

2x^2+2y^2+8x-20y-18=0

2 x^{2} + 2 y^{2} + 8 x - 20 y - 18 = 0

X^2+Y^2+6X-8Y=11

X^{2} + Y^{2} + 6 X - 8 Y = 11

x^2+y^2+2x-6y+9=0

x^{2} + y^{2} + 2 x - 6 y + 9 = 0

4x^2+36x+4y^2-24y+36=0

4 x^{2} + 36 x + 4 y^{2} - 24 y + 36 = 0

(x+3)^2+(y+5)^2=28

(x + 3)^{2} + (y + 5)^{2} = 28