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Beliebt Geometry >

2x^2+2y^2-40y=0

Lösung

2 x^{2} + 2 y^{2} - 40 y = 0

Lösung

(h, k) = (0, 10), a = 10, b = 10

Schritte zur Lösung

2 x^{2} + 2 y^{2} - 40 y = 0

Rewrite

2 x^{2} + 2 y^{2} - 40 y = 0

in the form of the standard ellipse equation

\frac{( x - 0 ) ^{2}}{1 0 ^{2}} + \frac{( y - 10 ) ^{2}}{1 0 ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (0, 10), a = 10, b = 10

b > a

therefore

b

is semi-major axis and

a

is semi-minor axis

Ellipse with center (h, k) = (0, 10), b = 10, a = 10

Graph

Beliebte Beispiele

(x^2+y^2-x)/(2x-x^2-y^2)>= 0

\frac{x ^{2} + y ^{2} - x}{2 x - x ^{2} - y ^{2}} \geq 0

4x^2+y^2-16x+6y-75=0

4 x^{2} + y^{2} - 16 x + 6 y - 75 = 0

4x^2-24x+(y^2)/(16)+y/8+573/16 =0

4 x^{2} - 24 x + \frac{y ^{2}}{16} + \frac{y}{8} + \frac{573}{16} = 0

((x-2)^2)/(64)+((y+4)^2)/(16)=1

\frac{( x - 2 ) ^{2}}{64} + \frac{( y + 4 ) ^{2}}{16} = 1

25x^2+16y^2-250x-32y+241=0

25 x^{2} + 16 y^{2} - 250 x - 32 y + 241 = 0