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Beliebt Geometry >

2x^2+y^2+16x-4y+32=0

Lösung

2 x^{2} + y^{2} + 16 x - 4 y + 32 = 0

Lösung

(h, k) = (- 4, 2), a = 2, b = 2

Schritte zur Lösung

2 x^{2} + y^{2} + 16 x - 4 y + 32 = 0

Rewrite

2 x^{2} + y^{2} + 16 x - 4 y + 32 = 0

in the form of the standard ellipse equation

\frac{( x - ( - 4 ) ) ^{2}}{( 2 ) ^{2}} + \frac{( y - 2 ) ^{2}}{2 ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (- 4, 2), a = 2, b = 2

b > a

therefore

b

is semi-major axis and

a

is semi-minor axis

Ellipse with center (h, k) = (- 4, 2), b = 2, a = 2

Graph

Beliebte Beispiele

((x-5)^2}{16}+\frac{(y-3)^2)/4 =1

\frac{( x - 5 ) ^{2}}{16} + \frac{( y - 3 ) ^{2}}{4} = 1

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4 y^{2} - 338 x + 32 y = - 169 x^{2} + 443

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2 x^{2} + y^{2} - 4 x + 8 y - 4 = 0

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25 x^{2} + 9 y^{2} - 250 x - 18 y + 409 = 0

9(x+2)^2+4(y+1)^2=1

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