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Beliebt Geometry >

9(x+2)^2+4(y+1)^2=1

Lösung

9 (x + 2)^{2} + 4 (y + 1)^{2} = 1

Lösung

(h, k) = (- 2, - 1), a = \frac{1}{3}, b = \frac{1}{2}

Schritte zur Lösung

9 (x + 2)^{2} + 4 (y + 1)^{2} = 1

Rewrite

9 (x + 2)^{2} + 4 (y + 1)^{2} = 1

in the form of the standard ellipse equation

\frac{( x - ( - 2 ) ) ^{2}}{( \frac{1}{3} ) ^{2}} + \frac{( y - ( - 1 ) ) ^{2}}{( \frac{1}{2} ) ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (- 2, - 1), a = \frac{1}{3}, b = \frac{1}{2}

b > a

therefore

b

is semi-major axis and

a

is semi-minor axis

Ellipse with center (h, k) = (- 2, - 1), b = \frac{1}{2}, a = \frac{1}{3}

Graph

Beliebte Beispiele

((x-1)^2)/6+((y-3)^2)/2 =1

\frac{( x - 1 ) ^{2}}{6} + \frac{( y - 3 ) ^{2}}{2} = 1

(12(x)^2)/(24)+(3y^2)/(24)= 24/24

\frac{12 ( x ) ^{2}}{24} + \frac{3 y ^{2}}{24} = \frac{24}{24}

((x-1)^2}{16}+\frac{(y+2)^2)/9 =1

\frac{( x - 1 ) ^{2}}{16} + \frac{( y + 2 ) ^{2}}{9} = 1

(y-6)^2+8x^2=64

(y - 6)^{2} + 8 x^{2} = 64

x^2+16y^2-128y+240=0

x^{2} + 16 y^{2} - 128 y + 240 = 0