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Beliebt Geometry >

foki y=+2x^2+2

Lösung

foki

y = + 2 x^{2} + 2

Lösung

(0, \frac{17}{8})

Schritte zur Lösung

Rewrite

y = 2 x^{2} + 2

in the standard form:

4 \cdot \frac{1}{8} (y - 2) = (x - 0)^{2}

(h, k) = (0, 2), p = \frac{1}{8}

Parabola is symmetric around the y-axis and so the focus lies a distance

p

from the center

(0, 2)

along the y-axis

(0, 2 + p)

= (0, 2 + \frac{1}{8})

Fasse zusammen

(0, \frac{17}{8})

Graph

Beliebte Beispiele

f oc i - x^{2} + 3 x - 5

foki y=-1/3 x^2

f oc i y = - \frac{1}{3} x^{2}

foki x^2=8y+2x-33

f oc i x^{2} = 8 y + 2 x - 33

foki (x-4)^2=20(y+5)

f oc i (x - 4)^{2} = 20 (y + 5)

foki y= 1/2 (1-2x-x^2)

f oc i y = \frac{1}{2} (1 - 2 x - x^{2})