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受欢迎的初等代数 >

(1+1/2)× (-2-3/4)

解答

(1 + \frac{1}{2}) \cdot (- 2 - \frac{3}{4})

解答

- \frac{33}{8}

+1

十进制

- 4.125

求解步骤

(1 + \frac{1}{2}) (- 2 - \frac{3}{4})

遵循 PEMDAS 运算顺序

计算括号内的值

(1 + \frac{1}{2}) : \frac{3}{2}

1 + \frac{1}{2}

1 + \frac{1}{2} = \frac{3}{2}

1 + \frac{1}{2}

将项转换为分式:

1 = \frac{1 \cdot 2}{2}

= \frac{1 \cdot 2}{2} + \frac{1}{2}

因为分母相等，所以合并分式:

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

= \frac{1 \cdot 2 + 1}{2}

1 \cdot 2 + 1 = 3

1 \cdot 2 + 1

数字相乘:

1 \cdot 2 = 2

= 2 + 1

数字相加:

2 + 1 = 3

= 3

= \frac{3}{2}

= \frac{3}{2}

= \frac{3}{2} (- 2 - \frac{3}{4})

计算括号内的值

(- 2 - \frac{3}{4}) : - \frac{11}{4}

- 2 - \frac{3}{4}

- 2 - \frac{3}{4} = - \frac{11}{4}

= - \frac{11}{4}

= \frac{3}{2} (- \frac{11}{4})

乘除（左右）

\frac{3}{2} (- \frac{11}{4}) : - \frac{33}{8}

\frac{3}{2} (- \frac{11}{4})

使用法则

a \cdot (- b) = - a \cdot b

\frac{3}{2} (- \frac{11}{4}) = - \frac{3}{2} \cdot \frac{11}{4}

使用分式法则:

\frac{a}{b} \cdot \frac{c}{d} = \frac{a \cdot c}{b \cdot d}

\frac{3}{2} \cdot \frac{11}{4} = \frac{3 \cdot 11}{2 \cdot 4}

= - \frac{3 \cdot 11}{2 \cdot 4}

数字相乘:

3 \cdot 11 = 33

= - \frac{33}{2 \cdot 4}

数字相乘:

2 \cdot 4 = 8

= - \frac{33}{8}

= - \frac{33}{8}

流行的例子

(7+3 1/8)+(14+6 1/4)

(7 + 3 \frac{1}{8}) + (14 + 6 \frac{1}{4})

5^{3} \times 3^{2}

1 4^{3} + 1 4^{3}

\frac{1}{4} (4) + 2

[- 7 + 5] - [2 - 5]