sec(x)=-sqrt(2),0<= x<= 2pi

Lösung

sec (x) = - 2, 0 \leq x \leq 2 π

x = \frac{3 π}{4}, x = \frac{5 π}{4}

Grad

x = 13 5^{\circ}, x = 22 5^{\circ}

Schritte zur Lösung

sec (x) = - 2, 0 \leq x \leq 2 π

Allgemeine Lösung für

sec (x) = - 2

sec (x)

Periodizitätstabelle mit

2 πn

Zyklus:

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} sec (x) 1 \frac{2 3}{3} 22 Undefined - 2 - 2 - \frac{2 3}{3} x π \frac{7 π}{6} \frac{5 π}{4} \frac{4 π}{3} \frac{3 π}{2} \frac{5 π}{3} \frac{7 π}{4} \frac{11 π}{6} sec (x) - 1 - \frac{2 3}{3} - 2 - 2 Undefined 22 \frac{2 3}{3}

x = \frac{3 π}{4} + 2 πn, x = \frac{5 π}{4} + 2 πn

x = \frac{3 π}{4} + 2 πn, x = \frac{5 π}{4} + 2 πn

Lösungen für den Bereich

0 \leq x \leq 2 π

x = \frac{3 π}{4}, x = \frac{5 π}{4}

so l v e f or t, g = sin (2 π f t)

3 sin (x) - cos (x) = - 3

- 8 sin (8 x) = 0

sin (θ) = - \frac{7}{25}

cos (\frac{θ}{2}) = - \frac{3}{2}