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受欢迎的三角函数 >

csc^2(x)+4csc(x)+4=0

解答

csc^{2} (x) + 4 csc (x) + 4 = 0

解答

x = \frac{7 π}{6} + 2 πn, x = \frac{11 π}{6} + 2 πn

+1

度数

x = 21 0^{\circ} + 36 0^{\circ} n, x = 33 0^{\circ} + 36 0^{\circ} n

求解步骤

csc^{2} (x) + 4 csc (x) + 4 = 0

用替代法求解

csc^{2} (x) + 4 csc (x) + 4 = 0

令

: csc (x) = u

u^{2} + 4 u + 4 = 0

u^{2} + 4 u + 4 = 0 : u = - 2

u^{2} + 4 u + 4 = 0

使用求根公式求解

u^{2} + 4 u + 4 = 0

二次方程求根公式:

若

a = 1, b = 4, c = 4

u_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 \cdot 1 \cdot 4}{2 \cdot 1}

u_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 \cdot 1 \cdot 4}{2 \cdot 1}

4^{2} - 4 \cdot 1 \cdot 4 = 0

4^{2} - 4 \cdot 1 \cdot 4

数字相乘:

4 \cdot 1 \cdot 4 = 16

= 4^{2} - 16

4^{2} = 16

= 16 - 16

数字相减:

16 - 16 = 0

= 0

u_{1, 2} = \frac{- 4 \pm 0}{2 \cdot 1}

u = \frac{- 4}{2 \cdot 1}

\frac{- 4}{2 \cdot 1} = - 2

\frac{- 4}{2 \cdot 1}

数字相乘:

2 \cdot 1 = 2

= \frac{- 4}{2}

使用分式法则:

\frac{- a}{b} = - \frac{a}{b}

= - \frac{4}{2}

数字相除:

\frac{4}{2} = 2

= - 2

u = - 2

二次方程组的解是:

u = - 2

u = csc (x)

代回

csc (x) = - 2

csc (x) = - 2

csc (x) = - 2 : x = \frac{7 π}{6} + 2 πn, x = \frac{11 π}{6} + 2 πn

csc (x) = - 2

csc (x) = - 2

的通解

csc (x)

周期表（周期为

2 πn

）：

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} csc (x) Undefiend 22 \frac{2 3}{3} 1 \frac{2 3}{3} 22 x π \frac{7 π}{6} \frac{5 π}{4} \frac{4 π}{3} \frac{3 π}{2} \frac{5 π}{3} \frac{7 π}{4} \frac{11 π}{6} csc (x) Undefiend - 2 - 2 - \frac{2 3}{3} - 1 - \frac{2 3}{3} - 2 - 2

x = \frac{7 π}{6} + 2 πn, x = \frac{11 π}{6} + 2 πn

x = \frac{7 π}{6} + 2 πn, x = \frac{11 π}{6} + 2 πn

合并所有解

x = \frac{7 π}{6} + 2 πn, x = \frac{11 π}{6} + 2 πn

作图

流行的例子

6sin^2(x)-cos(x)-4=0

6 sin^{2} (x) - cos (x) - 4 = 0

2sin(2x)cos(x)+sin(x)=0

2 sin (2 x) cos (x) + sin (x) = 0

4 cos (x) + 1 = 3

solvefor y,x=sqrt(sin(y))

so l v e f or y, x = sin (y)

sin(x)+sin(x)cos(x)=0

sin (x) + sin (x) cos (x) = 0