cos(θ)= 6/9

Lösung

cos (θ) = \frac{6}{9}

θ = 0.84106 \dots + 2 πn, θ = 2 π - 0.84106 \dots + 2 πn

Grad

θ = 48.18968 \dots^{\circ} + 36 0^{\circ} n, θ = 311.81031 \dots^{\circ} + 36 0^{\circ} n

Schritte zur Lösung

cos (θ) = \frac{6}{9}

Streiche die gemeinsamen Faktoren:

3

cos (θ) = \frac{2}{3}

Wende die Eigenschaften der Trigonometrie an

cos (θ) = \frac{2}{3}

Allgemeine Lösung für

cos (θ) = \frac{2}{3}

cos (x) = a \Rightarrow x = arccos (a) + 2 πn, x = 2 π - arccos (a) + 2 πn

θ = arccos (\frac{2}{3}) + 2 πn, θ = 2 π - arccos (\frac{2}{3}) + 2 πn

θ = arccos (\frac{2}{3}) + 2 πn, θ = 2 π - arccos (\frac{2}{3}) + 2 πn

Zeige Lösungen in Dezimalform

θ = 0.84106 \dots + 2 πn, θ = 2 π - 0.84106 \dots + 2 πn

sec (b) = 2

2 sin^{2} (x) - 4 sin (x) = cos^{2} (x) - 2

cos (\frac{θ}{2}) = - \frac{2}{2}

16 sin^{2} (x) + 24 sin (x) + 8 = 0

1 - 3 tan^{2} (x) = 0