cos(b)=0.3125

Lösung

cos (b) = 0.3125

b = 1.25297 \dots + 2 πn, b = 2 π - 1.25297 \dots + 2 πn

Grad

b = 71.79004 \dots^{\circ} + 36 0^{\circ} n, b = 288.20995 \dots^{\circ} + 36 0^{\circ} n

Schritte zur Lösung

cos (b) = 0.3125

Wende die Eigenschaften der Trigonometrie an

cos (b) = 0.3125

Allgemeine Lösung für

cos (b) = 0.3125

cos (x) = a \Rightarrow x = arccos (a) + 2 πn, x = 2 π - arccos (a) + 2 πn

b = arccos (0.3125) + 2 πn, b = 2 π - arccos (0.3125) + 2 πn

b = arccos (0.3125) + 2 πn, b = 2 π - arccos (0.3125) + 2 πn

Zeige Lösungen in Dezimalform

b = 1.25297 \dots + 2 πn, b = 2 π - 1.25297 \dots + 2 πn

sin (\frac{1}{2} x) - 1 = 0

- \frac{1}{16} sin (\frac{x}{4}) = 0

sin (x) cos (x) = cos^{2} (x)

so l v e f or x, sin (x - y) = 0

cos (2 θ) = 0.4