1/2 sinh(2x)-4/5 cosh(2x)+1=0

Solución

\frac{1}{2} sinh (2 x) - \frac{4}{5} cosh (2 x) + 1 = 0

x = \frac{1}{2} ln (\frac{10 - 61}{3}), x = \frac{1}{2} ln (\frac{10 + 61}{3})

Pasos de solución

\frac{1}{2} sinh (2 x) - \frac{4}{5} cosh (2 x) + 1 = 0

Re-escribir usando identidades trigonométricas

\frac{1}{2} \cdot \frac{e ^{2 x} - e ^{- 2 x}}{2} - \frac{4}{5} \cdot \frac{e ^{2 x} + e ^{- 2 x}}{2} + 1 = 0

\frac{1}{2} \cdot \frac{e ^{2 x} - e ^{- 2 x}}{2} - \frac{4}{5} \cdot \frac{e ^{2 x} + e ^{- 2 x}}{2} + 1 = 0 : x = \frac{1}{2} ln (\frac{10 - 61}{3}), x = \frac{1}{2} ln (\frac{10 + 61}{3})

x = \frac{1}{2} ln (\frac{10 - 61}{3}), x = \frac{1}{2} ln (\frac{10 + 61}{3})

7 sin^{2} (x) + 2 sin (x) - 2 = 0

3 cos (θ) - 1 = - 1

2 - 4 cos (x) = 0

csc (2 x) - 4 = 0

8 cos (2 x) = 42