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受欢迎的三角函数 >

2sec(θ)-7=0

解答

2 sec (θ) - 7 = 0

解答

θ = 1.28104 \dots + 2 πn, θ = 2 π - 1.28104 \dots + 2 πn

+1

度数

θ = 73.39845 \dots^{\circ} + 36 0^{\circ} n, θ = 286.60154 \dots^{\circ} + 36 0^{\circ} n

求解步骤

2 sec (θ) - 7 = 0

将

7

到右边

2 sec (θ) - 7 = 0

两边加上

7

2 sec (θ) - 7 + 7 = 0 + 7

化简

2 sec (θ) = 7

2 sec (θ) = 7

两边除以

2

2 sec (θ) = 7

两边除以

2

\frac{2 sec ( θ )}{2} = \frac{7}{2}

化简

sec (θ) = \frac{7}{2}

sec (θ) = \frac{7}{2}

使用反三角函数性质

sec (θ) = \frac{7}{2}

sec (θ) = \frac{7}{2}

的通解

sec (x) = a \Rightarrow x = arcsec (a) + 2 πn, x = 2 π - arcsec (a) + 2 πn

θ = arcsec (\frac{7}{2}) + 2 πn, θ = 2 π - arcsec (\frac{7}{2}) + 2 πn

θ = arcsec (\frac{7}{2}) + 2 πn, θ = 2 π - arcsec (\frac{7}{2}) + 2 πn

以小数形式表示解

θ = 1.28104 \dots + 2 πn, θ = 2 π - 1.28104 \dots + 2 πn

作图

流行的例子

tan(x)=2sqrt(3)

tan (x) = 23

-4sin(2x)-4cos(x)=0

- 4 sin (2 x) - 4 cos (x) = 0

2sin^2(4x)-2cos(4x)=1,o<= x<= 360

2 sin^{2} (4 x) - 2 cos (4 x) = 1, o^{\circ} \leq x \leq 36 0^{\circ}

sin (x) - 3 = 0

2sqrt(3)+4cos(θ)=0

23 + 4 cos (θ) = 0