2sin(1/2 x)=1,0<= x<= 12

Solución

2 sin (\frac{1}{2} x) = 1, 0^{\circ} \leq x \leq 1 2^{\circ}

Sin soluci \overset{o}{ˊ} n para x \in R

Pasos de solución

2 sin (\frac{1}{2} x) = 1, 0^{\circ} \leq x \leq 1 2^{\circ}

Dividir ambos lados entre

2

sin (\frac{1}{2} x) = \frac{1}{2}

Soluciones generales para

sin (\frac{1}{2} x) = \frac{1}{2}

\frac{1}{2} x = 3 0^{\circ} + 36 0^{\circ} n, \frac{1}{2} x = 15 0^{\circ} + 36 0^{\circ} n

Resolver

\frac{1}{2} x = 3 0^{\circ} + 36 0^{\circ} n : x = 6 0^{\circ} + 72 0^{\circ} n

Resolver

\frac{1}{2} x = 15 0^{\circ} + 36 0^{\circ} n : x = 30 0^{\circ} + 72 0^{\circ} n

x = 6 0^{\circ} + 72 0^{\circ} n, x = 30 0^{\circ} + 72 0^{\circ} n

Soluciones para el rango

0 \leq x \leq 1 2^{\circ}

Sin soluci \overset{o}{ˊ} n para x \in R

2 sin (\frac{π}{4} + x) \cdot sin (\frac{π}{4} - x) + sin^{2} (x) = 0

(2 sin (x) - 1) (cos (x) + 1) = 0

7 sin^{2} (x) - 6 = - 3 sin^{2} (x)

tan (b) = 4

1 sin (3 0^{\circ}) = 1.5 sin (x)