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人気のある三角関数 >

7sec(θ)=-9.2

解

7 sec (θ) = - 9.2

解

θ = 2.43544 \dots + 2 πn, θ = - 2.43544 \dots + 2 πn

+1

度

θ = 139.54091 \dots^{\circ} + 36 0^{\circ} n, θ = - 139.54091 \dots^{\circ} + 36 0^{\circ} n

解答ステップ

7 sec (θ) = - 9.2

以下で両辺を割る

7

7 sec (θ) = - 9.2

以下で両辺を割る

7

\frac{7 sec ( θ )}{7} = \frac{- 9.2}{7}

簡素化

\frac{7 sec ( θ )}{7} = \frac{- 9.2}{7}

簡素化

\frac{7 sec ( θ )}{7} : sec (θ)

\frac{7 sec ( θ )}{7}

数を割る:

\frac{7}{7} = 1

= sec (θ)

簡素化

\frac{- 9.2}{7} : - 1.31428 \dots

\frac{- 9.2}{7}

分数の規則を適用する:

\frac{- a}{b} = - \frac{a}{b}

= - \frac{9.2}{7}

数を割る:

\frac{9.2}{7} = 1.31428 \dots

= - 1.31428 \dots

sec (θ) = - 1.31428 \dots

sec (θ) = - 1.31428 \dots

sec (θ) = - 1.31428 \dots

三角関数の逆数プロパティを適用する

sec (θ) = - 1.31428 \dots

以下の一般解

sec (θ) = - 1.31428 \dots

sec (x) = - a \Rightarrow x = arcsec (- a) + 2 πn, x = - arcsec (- a) + 2 πn

θ = arcsec (- 1.31428 \dots) + 2 πn, θ = - arcsec (- 1.31428 \dots) + 2 πn

θ = arcsec (- 1.31428 \dots) + 2 πn, θ = - arcsec (- 1.31428 \dots) + 2 πn

10進法形式で解を証明する

θ = 2.43544 \dots + 2 πn, θ = - 2.43544 \dots + 2 πn

グラフ

人気の例

cos(x)=(3sqrt(3))/(2pi)

cos (x) = \frac{3 3}{2 π}

(sin(b))/(19)=(sin(74))/(19)

\frac{sin ( b )}{19} = \frac{sin ( 7 4 ^{\circ} )}{19}

- 8 cos^{2} (x) + 6 = 2

sin (x) = \frac{10}{20}

(sin(x)+cos(x))/(sin(x))=1-1/(tan(x))

\frac{sin ( x ) + cos ( x )}{sin ( x )} = 1 - \frac{1}{tan ( x )}