解
4sin(2x−0.4)−5cos(2x−0.4)=0
解
x=21.29605…+2πn
+1
度
x=37.12925…∘+90∘n解答ステップ
4sin(2x−0.4)−5cos(2x−0.4)=0
三角関数の公式を使用して書き換える
4sin(2x−0.4)−5cos(2x−0.4)=0
三角関数の公式を使用して書き換える
sin(2x−0.4)
角の差の公式を使用する: sin(s−t)=sin(s)cos(t)−cos(s)sin(t)=sin(2x)cos(0.4)−cos(2x)sin(0.4)
簡素化 sin(2x)cos(0.4)−cos(2x)sin(0.4):0.92106…sin(2x)−0.38941…cos(2x)
sin(2x)cos(0.4)−cos(2x)sin(0.4)
簡素化 cos(0.4):0.92106…
cos(0.4)
cos(0.4)=0.92106…=0.92106…
=0.92106…sin(2x)−sin(0.4)cos(2x)
簡素化 sin(0.4):0.38941…
sin(0.4)
sin(0.4)=0.38941…=0.38941…
=0.92106…sin(2x)−0.38941…cos(2x)
=0.92106…sin(2x)−0.38941…cos(2x)
角の差の公式を使用する: cos(s−t)=cos(s)cos(t)+sin(s)sin(t)=cos(2x)cos(0.4)+sin(2x)sin(0.4)
簡素化 cos(2x)cos(0.4)+sin(2x)sin(0.4):0.92106…cos(2x)+0.38941…sin(2x)
cos(2x)cos(0.4)+sin(2x)sin(0.4)
簡素化 cos(0.4):0.92106…
cos(0.4)
cos(0.4)=0.92106…=0.92106…
=0.92106…cos(2x)+sin(0.4)sin(2x)
簡素化 sin(0.4):0.38941…
sin(0.4)
sin(0.4)=0.38941…=0.38941…
=0.92106…cos(2x)+0.38941…sin(2x)
=0.92106…cos(2x)+0.38941…sin(2x)
4(0.92106…sin(2x)−0.38941…cos(2x))−5(0.92106…cos(2x)+0.38941…sin(2x))=0
簡素化 4(0.92106…sin(2x)−0.38941…cos(2x))−5(0.92106…cos(2x)+0.38941…sin(2x)):1.73715…sin(2x)−6.16297…cos(2x)
4(0.92106…sin(2x)−0.38941…cos(2x))−5(0.92106…cos(2x)+0.38941…sin(2x))
拡張 4(0.92106…sin(2x)−0.38941…cos(2x)):3.68424…sin(2x)−1.55767…cos(2x)
4(0.92106…sin(2x)−0.38941…cos(2x))
分配法則を適用する: a(b−c)=ab−aca=4,b=0.92106…sin(2x),c=0.38941…cos(2x)=4⋅0.92106…sin(2x)−4⋅0.38941…cos(2x)
簡素化 4⋅0.92106…sin(2x)−4⋅0.38941…cos(2x):3.68424…sin(2x)−1.55767…cos(2x)
4⋅0.92106…sin(2x)−4⋅0.38941…cos(2x)
数を乗じる:4⋅0.92106…=3.68424…=3.68424…sin(2x)−4⋅0.38941…cos(2x)
数を乗じる:4⋅0.38941…=1.55767…=3.68424…sin(2x)−1.55767…cos(2x)
=3.68424…sin(2x)−1.55767…cos(2x)
=3.68424…sin(2x)−1.55767…cos(2x)−5(0.92106…cos(2x)+0.38941…sin(2x))
拡張 −5(0.92106…cos(2x)+0.38941…sin(2x)):−4.60530…cos(2x)−1.94709…sin(2x)
−5(0.92106…cos(2x)+0.38941…sin(2x))
分配法則を適用する: a(b+c)=ab+aca=−5,b=0.92106…cos(2x),c=0.38941…sin(2x)=−5⋅0.92106…cos(2x)+(−5)⋅0.38941…sin(2x)
マイナス・プラスの規則を適用する+(−a)=−a=−5⋅0.92106…cos(2x)−5⋅0.38941…sin(2x)
簡素化 −5⋅0.92106…cos(2x)−5⋅0.38941…sin(2x):−4.60530…cos(2x)−1.94709…sin(2x)
−5⋅0.92106…cos(2x)−5⋅0.38941…sin(2x)
数を乗じる:5⋅0.92106…=4.60530…=−4.60530…cos(2x)−5⋅0.38941…sin(2x)
数を乗じる:5⋅0.38941…=1.94709…=−4.60530…cos(2x)−1.94709…sin(2x)
=−4.60530…cos(2x)−1.94709…sin(2x)
=3.68424…sin(2x)−1.55767…cos(2x)−4.60530…cos(2x)−1.94709…sin(2x)
簡素化 3.68424…sin(2x)−1.55767…cos(2x)−4.60530…cos(2x)−1.94709…sin(2x):1.73715…sin(2x)−6.16297…cos(2x)
3.68424…sin(2x)−1.55767…cos(2x)−4.60530…cos(2x)−1.94709…sin(2x)
類似した元を足す:−1.55767…cos(2x)−4.60530…cos(2x)=−6.16297…cos(2x)=3.68424…sin(2x)−6.16297…cos(2x)−1.94709…sin(2x)
類似した元を足す:3.68424…sin(2x)−1.94709…sin(2x)=1.73715…sin(2x)=1.73715…sin(2x)−6.16297…cos(2x)
=1.73715…sin(2x)−6.16297…cos(2x)
1.73715…sin(2x)−6.16297…cos(2x)=0
cos(2x),cos(2x)=0で両辺を割るcos(2x)1.73715…sin(2x)−6.16297…cos(2x)=cos(2x)0
簡素化cos(2x)1.73715…sin(2x)−6.16297…=0
基本的な三角関数の公式を使用する: cos(x)sin(x)=tan(x)1.73715…tan(2x)−6.16297…=0
1.73715…tan(2x)−6.16297…=0
6.16297…を右側に移動します
1.73715…tan(2x)−6.16297…=0
両辺に6.16297…を足す1.73715…tan(2x)−6.16297…+6.16297…=0+6.16297…
簡素化1.73715…tan(2x)=6.16297…
1.73715…tan(2x)=6.16297…
以下で両辺を割る1.73715…
1.73715…tan(2x)=6.16297…
以下で両辺を割る1.73715…1.73715…1.73715…tan(2x)=1.73715…6.16297…
簡素化tan(2x)=3.54774…
tan(2x)=3.54774…
三角関数の逆数プロパティを適用する
tan(2x)=3.54774…
以下の一般解 tan(2x)=3.54774…tan(x)=a⇒x=arctan(a)+πn2x=arctan(3.54774…)+πn
2x=arctan(3.54774…)+πn
解く 2x=arctan(3.54774…)+πn:x=2arctan(3.54774…)+2πn
2x=arctan(3.54774…)+πn
以下で両辺を割る2
2x=arctan(3.54774…)+πn
以下で両辺を割る222x=2arctan(3.54774…)+2πn
簡素化x=2arctan(3.54774…)+2πn
x=2arctan(3.54774…)+2πn
x=2arctan(3.54774…)+2πn
10進法形式で解を証明するx=21.29605…+2πn