beweisen 1+tan^2(θ)=sec^2(θ)

Lösung

beweisen

1 + tan^{2} (θ) = sec^{2} (θ)

Wahr

Schritte zur Lösung

1 + tan^{2} (θ) = sec^{2} (θ)

Verwende die Pythagoreische Identität:

tan^{2} (x) + 1 = sec^{2} (x)

\Rightarrow Wahr

p ro v e \frac{sin ( π - x )}{sin ( x + \frac{π}{2} )} = tan (x)

p ro v e \frac{cos ^{2} ( x )}{1 - sin ( x )} = \frac{csc ( x ) + 1}{csc ( x )}

p ro v e cos (3 x) = cos^{3} (x) - 3 sin^{2} (x) cos (x)

p ro v e (1 + cot^{2} (x)) tan (x) = csc (x) sec (x)

p ro v e sin (a + b) + sin (a - b) = 2 sin (a) cos (b)