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verificar arctan(x)=(arcsin(x))/(arccos(x))

Solución

verificar

arctan (x) = \frac{arcsin ( x )}{arccos ( x )}

Falso

Pasos de solución

arctan (x) = \frac{arcsin ( x )}{arccos ( x )}

Ambos lados no son iguales

Multiplicar

arctan (x) = \frac{arcsin ( x )}{arccos ( x )}

por

x = \frac{1}{2}

arctan (\frac{1}{2}) = 0.46364 \dots (Degrees : 26.5 7^{\circ})

arctan (\frac{1}{2})

Simplificar a una forma decimal

= 0.46364 \dots

\frac{arcsin ( \frac{1}{2} )}{arccos ( \frac{1}{2} )} = \frac{1}{2} (Decimal : Degrees : 0.5 28.6 5^{\circ})

\frac{arcsin ( \frac{1}{2} )}{arccos ( \frac{1}{2} )}

Utilizar la siguiente identidad trivial:

arcsin (\frac{1}{2}) = \frac{π}{6}

arcsin (\frac{1}{2})

x 0 \frac{1}{2} \frac{2}{2} \frac{3}{2} 1 arcsin (x) 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} arcsin (x) 0^{\circ} 3 0^{\circ} 4 5^{\circ} 6 0^{\circ} 9 0^{\circ}

= \frac{π}{6}

Utilizar la siguiente identidad trivial:

arccos (\frac{1}{2}) = \frac{π}{3}

arccos (\frac{1}{2})

x - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2} 0 \frac{1}{2} \frac{2}{2} \frac{3}{2} 1 arccos (x) π \frac{5 π}{6} \frac{3 π}{4} \frac{2 π}{3} \frac{π}{2} \frac{π}{3} \frac{π}{4} \frac{π}{6} 0 arccos (x) 18 0^{\circ} 15 0^{\circ} 13 5^{\circ} 12 0^{\circ} 9 0^{\circ} 6 0^{\circ} 4 5^{\circ} 3 0^{\circ} 0^{\circ}

= \frac{π}{3}

= \frac{\frac{π}{6}}{\frac{π}{3}}

Simplificar

\frac{\frac{π}{6}}{\frac{π}{3}} : \frac{1}{2}

\frac{\frac{π}{6}}{\frac{π}{3}}

Dividir fracciones:

\frac{\frac{a}{b}}{\frac{c}{d}} = \frac{a \cdot d}{b \cdot c}

= \frac{π 3}{6 π}

Eliminar los terminos comunes:

π

= \frac{3}{6}

Eliminar los terminos comunes:

3

= \frac{1}{2}

= \frac{1}{2}

Ambos lados no son iguales

\Rightarrow Falso

(cos (\frac{θ}{2}) - sin (\frac{θ}{2}))^{2} = 1 - sin (θ)

1 + sin (4 a) + sin (2 a) = - 2 cos (a)

(csc^{2} (θ)) (tan^{2} (θ)) - 1 = tan^{2} (θ)

cot (x) - cot (2 x) = csc (2 x)

\frac{csc ( θ ) + 1}{1 + sin ( θ )} = csc (θ)