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受欢迎的三角函数 >

cos(x)>(sqrt(2))/2

解答

cos (x) > \frac{2}{2}

解答

- \frac{π}{4} + 2 πn < x < \frac{π}{4} + 2 πn

+2

间隔符号

(- \frac{π}{4} + 2 πn, \frac{π}{4} + 2 πn)

十进制

- 0.78539 \dots + 2 πn < x < 0.78539 \dots + 2 πn

求解步骤

cos (x) > \frac{2}{2}

对于

cos (x) > a

，若

- 1 \leq a < 1

，则

- arccos (a) + 2 πn < x < arccos (a) + 2 πn

- arccos (\frac{2}{2}) + 2 πn < x < arccos (\frac{2}{2}) + 2 πn

化简

- arccos (\frac{2}{2}) : - \frac{π}{4}

- arccos (\frac{2}{2})

使用以下普通恒等式:

arccos (\frac{2}{2}) = \frac{π}{4}

x - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2} 0 \frac{1}{2} \frac{2}{2} \frac{3}{2} 1 arccos (x) π \frac{5 π}{6} \frac{3 π}{4} \frac{2 π}{3} \frac{π}{2} \frac{π}{3} \frac{π}{4} \frac{π}{6} 0 arccos (x) 18 0^{\circ} 15 0^{\circ} 13 5^{\circ} 12 0^{\circ} 9 0^{\circ} 6 0^{\circ} 4 5^{\circ} 3 0^{\circ} 0^{\circ}

= - \frac{π}{4}

化简

arccos (\frac{2}{2}) : \frac{π}{4}

arccos (\frac{2}{2})

使用以下普通恒等式:

arccos (\frac{2}{2}) = \frac{π}{4}

x - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2} 0 \frac{1}{2} \frac{2}{2} \frac{3}{2} 1 arccos (x) π \frac{5 π}{6} \frac{3 π}{4} \frac{2 π}{3} \frac{π}{2} \frac{π}{3} \frac{π}{4} \frac{π}{6} 0 arccos (x) 18 0^{\circ} 15 0^{\circ} 13 5^{\circ} 12 0^{\circ} 9 0^{\circ} 6 0^{\circ} 4 5^{\circ} 3 0^{\circ} 0^{\circ}

= \frac{π}{4}

- \frac{π}{4} + 2 πn < x < \frac{π}{4} + 2 πn

流行的例子

cos(x)<(sqrt(2))/2

cos (x) < \frac{2}{2}

cot (x) < 1

2 sin (x) - 1 \geq 0

sin^2(x)+1/2*sin(x)>0

sin^{2} (x) + \frac{1}{2} \cdot sin (x) > 0

- sin (x) > 0