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受欢迎的三角函数 >

6cos(x)+2=0

解答

6 cos (x) + 2 = 0

解答

x = 1.91063 \dots + 2 πn, x = - 1.91063 \dots + 2 πn

+1

度数

x = 109.47122 \dots^{\circ} + 36 0^{\circ} n, x = - 109.47122 \dots^{\circ} + 36 0^{\circ} n

求解步骤

6 cos (x) + 2 = 0

将

2

到右边

6 cos (x) + 2 = 0

两边减去

2

6 cos (x) + 2 - 2 = 0 - 2

化简

6 cos (x) = - 2

6 cos (x) = - 2

两边除以

6

6 cos (x) = - 2

两边除以

6

\frac{6 cos ( x )}{6} = \frac{- 2}{6}

化简

\frac{6 cos ( x )}{6} = \frac{- 2}{6}

化简

\frac{6 cos ( x )}{6} : cos (x)

\frac{6 cos ( x )}{6}

数字相除:

\frac{6}{6} = 1

= cos (x)

化简

\frac{- 2}{6} : - \frac{1}{3}

\frac{- 2}{6}

使用分式法则:

\frac{- a}{b} = - \frac{a}{b}

= - \frac{2}{6}

约分:

2

= - \frac{1}{3}

cos (x) = - \frac{1}{3}

cos (x) = - \frac{1}{3}

cos (x) = - \frac{1}{3}

使用反三角函数性质

cos (x) = - \frac{1}{3}

cos (x) = - \frac{1}{3}

的通解

cos (x) = - a \Rightarrow x = arccos (- a) + 2 πn, x = - arccos (- a) + 2 πn

x = arccos (- \frac{1}{3}) + 2 πn, x = - arccos (- \frac{1}{3}) + 2 πn

x = arccos (- \frac{1}{3}) + 2 πn, x = - arccos (- \frac{1}{3}) + 2 πn

以小数形式表示解

x = 1.91063 \dots + 2 πn, x = - 1.91063 \dots + 2 πn

作图

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