8cos(x+10)=5

Solución

8 cos (x + 1 0^{\circ}) = 5

x = 0.89566 \dots + 36 0^{\circ} n - 1 0^{\circ}, x = 36 0^{\circ} - 0.89566 \dots + 36 0^{\circ} n - 1 0^{\circ}

Pasos de solución

8 cos (x + 1 0^{\circ}) = 5

Dividir ambos lados entre

8

cos (x + 1 0^{\circ}) = \frac{5}{8}

Aplicar propiedades trigonométricas inversas

x + 1 0^{\circ} = arccos (\frac{5}{8}) + 36 0^{\circ} n, x + 1 0^{\circ} = 36 0^{\circ} - arccos (\frac{5}{8}) + 36 0^{\circ} n

Resolver

x + 1 0^{\circ} = arccos (\frac{5}{8}) + 36 0^{\circ} n : x = arccos (\frac{5}{8}) + 36 0^{\circ} n - 1 0^{\circ}

Resolver

x + 1 0^{\circ} = 36 0^{\circ} - arccos (\frac{5}{8}) + 36 0^{\circ} n : x = 36 0^{\circ} - arccos (\frac{5}{8}) + 36 0^{\circ} n - 1 0^{\circ}

x = arccos (\frac{5}{8}) + 36 0^{\circ} n - 1 0^{\circ}, x = 36 0^{\circ} - arccos (\frac{5}{8}) + 36 0^{\circ} n - 1 0^{\circ}

Mostrar soluciones en forma decimal

x = 0.89566 \dots + 36 0^{\circ} n - 1 0^{\circ}, x = 36 0^{\circ} - 0.89566 \dots + 36 0^{\circ} n - 1 0^{\circ}

cos^{2} (x) + cos (- x) = 0

x, ln (y) + y^{2} = - cos (x)

tan (x) = 1.33

cot (x) = 5

8^{2} = 1 4^{2} + 1 9^{2} - 2 (14) (19) cos (C)