1sin(45)=2.42sin(r)

Solución

1 sin (4 5^{\circ}) = 2.42 sin (r)

r = 0.29651 \dots + 36 0^{\circ} n, r = 18 0^{\circ} - 0.29651 \dots + 36 0^{\circ} n

Pasos de solución

1 \cdot sin (4 5^{\circ}) = 2.42 sin (r)

sin (4 5^{\circ}) = \frac{2}{2}

1 \cdot \frac{2}{2} = 2.42 sin (r)

Intercambiar lados

2.42 sin (r) = 1 \cdot \frac{2}{2}

Multiplicar ambos lados por

100

242 sin (r) = 502

Dividir ambos lados entre

242

sin (r) = \frac{25 2}{121}

Aplicar propiedades trigonométricas inversas

r = arcsin (\frac{25 2}{121}) + 36 0^{\circ} n, r = 18 0^{\circ} - arcsin (\frac{25 2}{121}) + 36 0^{\circ} n

Mostrar soluciones en forma decimal

r = 0.29651 \dots + 36 0^{\circ} n, r = 18 0^{\circ} - 0.29651 \dots + 36 0^{\circ} n

sec (x) = 4 sin (x)

sinh (nπ) = 0

x, z = sin (x y^{2})

3 sin^{2} (θ) + 2 cos (2 θ) = 1

sin^{4} (x) = 1