6/pi-4sin(2x)=0

Solución

\frac{6}{π} - 4 sin (2 x) = 0

x = \frac{0.49776 \dots}{2} + πn, x = \frac{π}{2} - \frac{0.49776 \dots}{2} + πn

Pasos de solución

\frac{6}{π} - 4 sin (2 x) = 0

Mover

\frac{6}{π}

al lado derecho

- 4 sin (2 x) = - \frac{6}{π}

Dividir ambos lados entre

- 4

sin (2 x) = \frac{3}{2 π}

Aplicar propiedades trigonométricas inversas

2 x = arcsin (\frac{3}{2 π}) + 2 πn, 2 x = π - arcsin (\frac{3}{2 π}) + 2 πn

Resolver

2 x = arcsin (\frac{3}{2 π}) + 2 πn : x = \frac{arcsin ( \frac{3}{2 π} )}{2} + πn

Resolver

2 x = π - arcsin (\frac{3}{2 π}) + 2 πn : x = \frac{π}{2} - \frac{arcsin ( \frac{3}{2 π} )}{2} + πn

x = \frac{arcsin ( \frac{3}{2 π} )}{2} + πn, x = \frac{π}{2} - \frac{arcsin ( \frac{3}{2 π} )}{2} + πn

Mostrar soluciones en forma decimal

x = \frac{0.49776 \dots}{2} + πn, x = \frac{π}{2} - \frac{0.49776 \dots}{2} + πn

sin (t) = \frac{1}{5}

sin^{2} (x) + \frac{1}{2} sin (x) = 0

sin (θ) = \frac{- 1}{2}

(sin (a) + cos (a))^{2} = 1 + 2, a cos (a)

4 sin (z) cos^{2} (z) = 3 sin (z)