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受欢迎的三角函数 >

(sin(115))/(20)=(sin(b))/(11)

解答

\frac{sin ( 11 5 ^{\circ} )}{20} = \frac{sin ( b )}{11}

解答

b = 0.52183 \dots + 36 0^{\circ} n, b = 18 0^{\circ} - 0.52183 \dots + 36 0^{\circ} n

+1

弧度

b = 0.52183 \dots + 2 πn, b = π - 0.52183 \dots + 2 πn

求解步骤

\frac{sin ( 11 5 ^{\circ} )}{20} = \frac{sin ( b )}{11}

交换两边

\frac{sin ( b )}{11} = \frac{sin ( 11 5 ^{\circ} )}{20}

在两边乘以

10

\frac{sin ( b )}{11} = \frac{sin ( 11 5 ^{\circ} )}{20}

在两边乘以

10

\frac{sin ( b )}{11} \cdot 10 = \frac{sin ( 11 5 ^{\circ} )}{20} \cdot 10

化简

\frac{sin ( b )}{11} \cdot 10 = \frac{sin ( 11 5 ^{\circ} )}{20} \cdot 10

化简

\frac{sin ( b )}{11} \cdot 10 : \frac{10 sin ( b )}{11}

\frac{sin ( b )}{11} \cdot 10

分式相乘:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{sin ( b ) \cdot 10}{11}

化简

\frac{sin ( 11 5 ^{\circ} )}{20} \cdot 10 : \frac{sin ( 11 5 ^{\circ} )}{2}

\frac{sin ( 11 5 ^{\circ} )}{20} \cdot 10

分式相乘:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{sin ( 11 5 ^{\circ} ) \cdot 10}{20}

约分:

10

= \frac{sin ( 11 5 ^{\circ} )}{2}

\frac{10 sin ( b )}{11} = \frac{sin ( 11 5 ^{\circ} )}{2}

\frac{10 sin ( b )}{11} = \frac{sin ( 11 5 ^{\circ} )}{2}

\frac{10 sin ( b )}{11} = \frac{sin ( 11 5 ^{\circ} )}{2}

在两边乘以

11

\frac{10 sin ( b )}{11} = \frac{sin ( 11 5 ^{\circ} )}{2}

在两边乘以

11

\frac{11 \cdot 10 sin ( b )}{11} = \frac{11 sin ( 11 5 ^{\circ} )}{2}

化简

10 sin (b) = \frac{11 sin ( 11 5 ^{\circ} )}{2}

10 sin (b) = \frac{11 sin ( 11 5 ^{\circ} )}{2}

两边除以

10

10 sin (b) = \frac{11 sin ( 11 5 ^{\circ} )}{2}

两边除以

10

\frac{10 sin ( b )}{10} = \frac{\frac{11 s i n ( 11 5 ^{\circ} )}{2}}{10}

化简

\frac{10 sin ( b )}{10} = \frac{\frac{11 s i n ( 11 5 ^{\circ} )}{2}}{10}

化简

\frac{10 sin ( b )}{10} : sin (b)

\frac{10 sin ( b )}{10}

数字相除:

\frac{10}{10} = 1

= sin (b)

化简

\frac{\frac{11 s i n ( 11 5 ^{\circ} )}{2}}{10} : \frac{11 sin ( 11 5 ^{\circ} )}{20}

\frac{\frac{11 s i n ( 11 5 ^{\circ} )}{2}}{10}

使用分式法则:

\frac{\frac{b}{c}}{a} = \frac{b}{c \cdot a}

= \frac{11 sin ( 11 5 ^{\circ} )}{2 \cdot 10}

数字相乘:

2 \cdot 10 = 20

= \frac{11 sin ( 11 5 ^{\circ} )}{20}

sin (b) = \frac{11 sin ( 11 5 ^{\circ} )}{20}

sin (b) = \frac{11 sin ( 11 5 ^{\circ} )}{20}

sin (b) = \frac{11 sin ( 11 5 ^{\circ} )}{20}

使用反三角函数性质

sin (b) = \frac{11 sin ( 11 5 ^{\circ} )}{20}

sin (b) = \frac{11 sin ( 11 5 ^{\circ} )}{20}

的通解

sin (x) = a \Rightarrow x = arcsin (a) + 36 0^{\circ} n, x = 18 0^{\circ} - arcsin (a) + 36 0^{\circ} n

b = arcsin (\frac{11 sin ( 11 5 ^{\circ} )}{20}) + 36 0^{\circ} n, b = 18 0^{\circ} - arcsin (\frac{11 sin ( 11 5 ^{\circ} )}{20}) + 36 0^{\circ} n

b = arcsin (\frac{11 sin ( 11 5 ^{\circ} )}{20}) + 36 0^{\circ} n, b = 18 0^{\circ} - arcsin (\frac{11 sin ( 11 5 ^{\circ} )}{20}) + 36 0^{\circ} n

以小数形式表示解

b = 0.52183 \dots + 36 0^{\circ} n, b = 18 0^{\circ} - 0.52183 \dots + 36 0^{\circ} n

作图

流行的例子

cos(θ)=(25)/(sqrt(714))

cos (θ) = \frac{25}{714}

3sec^2(x)-4=0,0<= x<2pi

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3cos(2x)+7sin(x)-5=0

3 cos (2 x) + 7 sin (x) - 5 = 0

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solvefor x,sin(x/5)=-(sqrt(3))/2

so l v e f or x, sin (\frac{x}{5}) = - \frac{3}{2}