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人気のある三角関数 >

3tan^2(x)=2sec^2(x)+1,0<= x<= 180

解

3 tan^{2} (x) = 2 sec^{2} (x) + 1, 0^{\circ} \leq x \leq 18 0^{\circ}

解

x = 6 0^{\circ}, x = 12 0^{\circ}

+1

ラジアン

x = \frac{π}{3}, x = \frac{2 π}{3}

解答ステップ

3 tan^{2} (x) = 2 sec^{2} (x) + 1, 0^{\circ} \leq x \leq 18 0^{\circ}

両辺から

2 sec^{2} (x) + 1

を引く

3 tan^{2} (x) - 2 sec^{2} (x) - 1 = 0

三角関数の公式を使用して書き換える

- 1 - 2 sec^{2} (x) + 3 tan^{2} (x)

ピタゴラスの公式を使用する:

tan^{2} (x) + 1 = sec^{2} (x)

tan^{2} (x) = sec^{2} (x) - 1

= - 1 - 2 sec^{2} (x) + 3 (sec^{2} (x) - 1)

簡素化

- 1 - 2 sec^{2} (x) + 3 (sec^{2} (x) - 1) : sec^{2} (x) - 4

- 1 - 2 sec^{2} (x) + 3 (sec^{2} (x) - 1)

拡張

3 (sec^{2} (x) - 1) : 3 sec^{2} (x) - 3

3 (sec^{2} (x) - 1)

分配法則を適用する:

a (b - c) = ab - a c

a = 3, b = sec^{2} (x), c = 1

= 3 sec^{2} (x) - 3 \cdot 1

数を乗じる:

3 \cdot 1 = 3

= 3 sec^{2} (x) - 3

= - 1 - 2 sec^{2} (x) + 3 sec^{2} (x) - 3

簡素化

- 1 - 2 sec^{2} (x) + 3 sec^{2} (x) - 3 : sec^{2} (x) - 4

- 1 - 2 sec^{2} (x) + 3 sec^{2} (x) - 3

類似した元を足す:

- 2 sec^{2} (x) + 3 sec^{2} (x) = sec^{2} (x)

= - 1 + sec^{2} (x) - 3

条件のようなグループ

= sec^{2} (x) - 1 - 3

数を引く:

- 1 - 3 = - 4

= sec^{2} (x) - 4

= sec^{2} (x) - 4

= sec^{2} (x) - 4

- 4 + sec^{2} (x) = 0

置換で解く

- 4 + sec^{2} (x) = 0

仮定:

sec (x) = u

- 4 + u^{2} = 0

- 4 + u^{2} = 0 : u = 2, u = - 2

- 4 + u^{2} = 0

4

を右側に移動します

- 4 + u^{2} = 0

両辺に

4

を足す

- 4 + u^{2} + 4 = 0 + 4

簡素化

u^{2} = 4

u^{2} = 4

x^{2} = f (a)

の場合, 解は

x = f (a), - f (a)

u = 4, u = - 4

4 = 2

4

数を因数に分解する:

4 = 2^{2}

= 2^{2}

累乗根の規則を適用する:

n a^{n} = a

2^{2} = 2

= 2

- 4 = - 2

- 4

4 = 2

4

数を因数に分解する:

4 = 2^{2}

= 2^{2}

累乗根の規則を適用する:

n a^{n} = a

2^{2} = 2

= 2

= - 2

u = 2, u = - 2

代用を戻す

u = sec (x)

sec (x) = 2, sec (x) = - 2

sec (x) = 2, sec (x) = - 2

sec (x) = 2, 0 \leq x \leq 18 0^{\circ} : x = 6 0^{\circ}

sec (x) = 2, 0 \leq x \leq 18 0^{\circ}

以下の一般解

sec (x) = 2

sec (x)

36 0^{\circ} n

循環を含む周期性テーブル :

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} sec (x) 1 \frac{2 3}{3} 22 Undefined - 2 - 2 - \frac{2 3}{3} x π \frac{7 π}{6} \frac{5 π}{4} \frac{4 π}{3} \frac{3 π}{2} \frac{5 π}{3} \frac{7 π}{4} \frac{11 π}{6} sec (x) - 1 - \frac{2 3}{3} - 2 - 2 Undefined 22 \frac{2 3}{3}

x = 6 0^{\circ} + 36 0^{\circ} n, x = 30 0^{\circ} + 36 0^{\circ} n

x = 6 0^{\circ} + 36 0^{\circ} n, x = 30 0^{\circ} + 36 0^{\circ} n

範囲の解答

0 \leq x \leq 18 0^{\circ}

x = 6 0^{\circ}

sec (x) = - 2, 0 \leq x \leq 18 0^{\circ} : x = 12 0^{\circ}

sec (x) = - 2, 0 \leq x \leq 18 0^{\circ}

以下の一般解

sec (x) = - 2

sec (x)

36 0^{\circ} n

循環を含む周期性テーブル :

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} sec (x) 1 \frac{2 3}{3} 22 Undefined - 2 - 2 - \frac{2 3}{3} x π \frac{7 π}{6} \frac{5 π}{4} \frac{4 π}{3} \frac{3 π}{2} \frac{5 π}{3} \frac{7 π}{4} \frac{11 π}{6} sec (x) - 1 - \frac{2 3}{3} - 2 - 2 Undefined 22 \frac{2 3}{3}

x = 12 0^{\circ} + 36 0^{\circ} n, x = 24 0^{\circ} + 36 0^{\circ} n

x = 12 0^{\circ} + 36 0^{\circ} n, x = 24 0^{\circ} + 36 0^{\circ} n

範囲の解答

0 \leq x \leq 18 0^{\circ}

x = 12 0^{\circ}

すべての解を組み合わせる

x = 6 0^{\circ}, x = 12 0^{\circ}

グラフ

人気の例

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sinh (x) = \frac{5}{12}, cosh (x)

sin (x) = cos (1 9^{\circ})

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