4csc(θ+pi/3)=2

解答

4 csc (θ + \frac{π}{3}) = 2

θ \in R 无解

求解步骤

4 csc (θ + \frac{π}{3}) = 2

两边除以

4

4 csc (θ + \frac{π}{3}) = 2

两边除以

4

\frac{4 csc ( θ + \frac{π}{3} )}{4} = \frac{2}{4}

化简

csc (θ + \frac{π}{3}) = \frac{1}{2}

csc (θ + \frac{π}{3}) = \frac{1}{2}

csc (x) \leq - 1 or csc (x) \geq 1

θ \in R 无解

sin (x + 2^{\circ}) = cos (x - 2^{\circ})

cos (x) = \frac{2}{6}

sec (θ) - 2 = 0, 0 \leq θ \leq 2 π

sin (A) - 0.1 \cdot cos (A) = \frac{6.94}{9.8}

so l v e f or t, s = 2 arctan (t)