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Popular >

solvefor t,x=1-2cos(2t)

Solución

resolver para

t, x = 1 - 2 cos (2 t)

Solución

t = \frac{arccos ( - \frac{x - 1}{2} )}{2} + πn, t = - \frac{arccos ( - \frac{x - 1}{2} )}{2} + πn

Pasos de solución

x = 1 - 2 cos (2 t)

Intercambiar lados

1 - 2 cos (2 t) = x

Mover

1

al lado derecho

1 - 2 cos (2 t) = x

Restar

1

de ambos lados

1 - 2 cos (2 t) - 1 = x - 1

Simplificar

- 2 cos (2 t) = x - 1

- 2 cos (2 t) = x - 1

Dividir ambos lados entre

- 2

- 2 cos (2 t) = x - 1

Dividir ambos lados entre

- 2

\frac{- 2 cos ( 2 t )}{- 2} = \frac{x}{- 2} - \frac{1}{- 2}

Simplificar

\frac{- 2 cos ( 2 t )}{- 2} = \frac{x}{- 2} - \frac{1}{- 2}

Simplificar

\frac{- 2 cos ( 2 t )}{- 2} : cos (2 t)

\frac{- 2 cos ( 2 t )}{- 2}

Aplicar las propiedades de las fracciones:

\frac{- a}{- b} = \frac{a}{b}

= \frac{2 cos ( 2 t )}{2}

Dividir:

\frac{2}{2} = 1

= cos (2 t)

Simplificar

\frac{x}{- 2} - \frac{1}{- 2} : - \frac{x - 1}{2}

\frac{x}{- 2} - \frac{1}{- 2}

Aplicar la regla

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

= \frac{x - 1}{- 2}

Aplicar las propiedades de las fracciones:

\frac{a}{- b} = - \frac{a}{b}

= - \frac{x - 1}{2}

cos (2 t) = - \frac{x - 1}{2}

cos (2 t) = - \frac{x - 1}{2}

cos (2 t) = - \frac{x - 1}{2}

Aplicar propiedades trigonométricas inversas

cos (2 t) = - \frac{x - 1}{2}

Soluciones generales para

cos (2 t) = - \frac{x - 1}{2}

cos (x) = a \Rightarrow x = arccos (a) + 2 πn, x = - arccos (a) + 2 πn

2 t = arccos (- \frac{x - 1}{2}) + 2 πn, 2 t = - arccos (- \frac{x - 1}{2}) + 2 πn

2 t = arccos (- \frac{x - 1}{2}) + 2 πn, 2 t = - arccos (- \frac{x - 1}{2}) + 2 πn

Resolver

2 t = arccos (- \frac{x - 1}{2}) + 2 πn : t = \frac{arccos ( - \frac{x - 1}{2} )}{2} + πn

2 t = arccos (- \frac{x - 1}{2}) + 2 πn

Dividir ambos lados entre

2

2 t = arccos (- \frac{x - 1}{2}) + 2 πn

Dividir ambos lados entre

2

\frac{2 t}{2} = \frac{arccos ( - \frac{x - 1}{2} )}{2} + \frac{2 πn}{2}

Simplificar

t = \frac{arccos ( - \frac{x - 1}{2} )}{2} + πn

t = \frac{arccos ( - \frac{x - 1}{2} )}{2} + πn

Resolver

2 t = - arccos (- \frac{x - 1}{2}) + 2 πn : t = - \frac{arccos ( - \frac{x - 1}{2} )}{2} + πn

2 t = - arccos (- \frac{x - 1}{2}) + 2 πn

Dividir ambos lados entre

2

2 t = - arccos (- \frac{x - 1}{2}) + 2 πn

Dividir ambos lados entre

2

\frac{2 t}{2} = - \frac{arccos ( - \frac{x - 1}{2} )}{2} + \frac{2 πn}{2}

Simplificar

t = - \frac{arccos ( - \frac{x - 1}{2} )}{2} + πn

t = - \frac{arccos ( - \frac{x - 1}{2} )}{2} + πn

t = \frac{arccos ( - \frac{x - 1}{2} )}{2} + πn, t = - \frac{arccos ( - \frac{x - 1}{2} )}{2} + πn

Ejemplos populares

solvefor x,sin(3x)=-(sqrt(3))/2 resolver para

x, sin (3 x) = - \frac{3}{2}

cos (x) = 0.587

(sec(x)+csc(x))/(1+tan(x))=sin(x)

\frac{sec ( x ) + csc ( x )}{1 + tan ( x )} = sin (x)

sec(x)-(sin(x))/(cos(x))=cos(x)

sec (x) - \frac{sin ( x )}{cos ( x )} = cos (x)

- 10 sin^{2} (t) = 0