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tan^2(x)+5cos(x)-8=0

Solución

tan^{2} (x) + 5 cos (x) - 8 = 0

Solución

x = 1.88390 \dots + 2 πn, x = - 1.88390 \dots + 2 πn, x = 1.18685 \dots + 2 πn, x = 2 π - 1.18685 \dots + 2 πn

Grados

x = 107.93989 \dots^{\circ} + 36 0^{\circ} n, x = - 107.93989 \dots^{\circ} + 36 0^{\circ} n, x = 68.00170 \dots^{\circ} + 36 0^{\circ} n, x = 291.99829 \dots^{\circ} + 36 0^{\circ} n

Pasos de solución

tan^{2} (x) + 5 cos (x) - 8 = 0

Re-escribir usando identidades trigonométricas

- 8 + tan^{2} (x) + 5 cos (x)

Utilizar la identidad trigonométrica básica:

tan (x) = \frac{sin ( x )}{cos ( x )}

= - 8 + (\frac{sin ( x )}{cos ( x )})^{2} + 5 cos (x)

Aplicar las leyes de los exponentes:

(\frac{a}{b})^{c} = \frac{a ^{c}}{b ^{c}}

= - 8 + \frac{sin ^{2} ( x )}{cos ^{2} ( x )} + 5 cos (x)

Utilizar la identidad pitagórica:

cos^{2} (x) + sin^{2} (x) = 1

sin^{2} (x) = 1 - cos^{2} (x)

= - 8 + \frac{1 - cos ^{2} ( x )}{cos ^{2} ( x )} + 5 cos (x)

- 8 + \frac{1 - cos ^{2} ( x )}{cos ^{2} ( x )} + 5 cos (x) = 0

Usando el método de sustitución

- 8 + \frac{1 - cos ^{2} ( x )}{cos ^{2} ( x )} + 5 cos (x) = 0

Sea:

cos (x) = u

- 8 + \frac{1 - u ^{2}}{u ^{2}} + 5 u = 0

- 8 + \frac{1 - u ^{2}}{u ^{2}} + 5 u = 0 : u \approx - 0.30801 \dots, u \approx 0.37457 \dots, u \approx 1.73344 \dots

- 8 + \frac{1 - u ^{2}}{u ^{2}} + 5 u = 0

Multiplicar ambos lados por

u^{2}

- 8 + \frac{1 - u ^{2}}{u ^{2}} + 5 u = 0

Multiplicar ambos lados por

u^{2}

- 8 u^{2} + \frac{1 - u ^{2}}{u ^{2}} u^{2} + 5 u u^{2} = 0 \cdot u^{2}

Simplificar

- 8 u^{2} + \frac{1 - u ^{2}}{u ^{2}} u^{2} + 5 u u^{2} = 0 \cdot u^{2}

Simplificar

\frac{1 - u ^{2}}{u ^{2}} u^{2} : 1 - u^{2}

\frac{1 - u ^{2}}{u ^{2}} u^{2}

Multiplicar fracciones:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{( 1 - u ^{2} ) u ^{2}}{u ^{2}}

Eliminar los terminos comunes:

u^{2}

= 1 - u^{2}

Simplificar

5 u u^{2} : 5 u^{3}

5 u u^{2}

Aplicar las leyes de los exponentes:

a^{b} \cdot a^{c} = a^{b + c}

u u^{2} = u^{1 + 2}

= 5 u^{1 + 2}

Sumar:

1 + 2 = 3

= 5 u^{3}

Simplificar

0 \cdot u^{2} : 0

0 \cdot u^{2}

Aplicar la regla

0 \cdot a = 0

= 0

- 8 u^{2} + 1 - u^{2} + 5 u^{3} = 0

Simplificar

- 8 u^{2} + 1 - u^{2} + 5 u^{3} : 5 u^{3} - 9 u^{2} + 1

- 8 u^{2} + 1 - u^{2} + 5 u^{3}

Agrupar términos semejantes

= 5 u^{3} - 8 u^{2} - u^{2} + 1

Sumar elementos similares:

- 8 u^{2} - u^{2} = - 9 u^{2}

= 5 u^{3} - 9 u^{2} + 1

5 u^{3} - 9 u^{2} + 1 = 0

5 u^{3} - 9 u^{2} + 1 = 0

5 u^{3} - 9 u^{2} + 1 = 0

Resolver

5 u^{3} - 9 u^{2} + 1 = 0 : u \approx - 0.30801 \dots, u \approx 0.37457 \dots, u \approx 1.73344 \dots

5 u^{3} - 9 u^{2} + 1 = 0

Encontrar una solución para

5 u^{3} - 9 u^{2} + 1 = 0

utilizando el método de Newton-Raphson:

u \approx - 0.30801 \dots

5 u^{3} - 9 u^{2} + 1 = 0

Definición del método de Newton-Raphson

f (u) = 5 u^{3} - 9 u^{2} + 1

Hallar

f^{^{'}} (u) : 15 u^{2} - 18 u

\frac{d}{d u} (5 u^{3} - 9 u^{2} + 1)

Aplicar la regla de la suma/diferencia:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d u} (5 u^{3}) - \frac{d}{d u} (9 u^{2}) + \frac{d}{d u} (1)

\frac{d}{d u} (5 u^{3}) = 15 u^{2}

\frac{d}{d u} (5 u^{3})

Sacar la constante:

(a \cdot f)^{'} = a \cdot f^{'}

= 5 \frac{d}{d u} (u^{3})

Aplicar la regla de la potencia:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= 5 \cdot 3 u^{3 - 1}

Simplificar

= 15 u^{2}

\frac{d}{d u} (9 u^{2}) = 18 u

\frac{d}{d u} (9 u^{2})

Sacar la constante:

(a \cdot f)^{'} = a \cdot f^{'}

= 9 \frac{d}{d u} (u^{2})

Aplicar la regla de la potencia:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= 9 \cdot 2 u^{2 - 1}

Simplificar

= 18 u

\frac{d}{d u} (1) = 0

\frac{d}{d u} (1)

Derivada de una constante:

\frac{d}{d x} (a) = 0

= 0

= 15 u^{2} - 18 u + 0

Simplificar

= 15 u^{2} - 18 u

Sea

u_{0} = - 1

Calcular

u_{n + 1}

hasta que

Δ u_{n + 1} < 0.000001

u_{1} = - 0.60606 \dots : Δ u_{1} = 0.39393 \dots

f (u_{0}) = 5 (- 1)^{3} - 9 (- 1)^{2} + 1 = - 13

f^{^{'}} (u_{0}) = 15 (- 1)^{2} - 18 (- 1) = 33

u_{1} = - 0.60606 \dots

Δ u_{1} = ∣ - 0.60606 \dots - (- 1) ∣ = 0.39393 \dots

Δ u_{1} = 0.39393 \dots

u_{2} = - 0.39783 \dots : Δ u_{2} = 0.20822 \dots

f (u_{1}) = 5 (- 0.60606 \dots)^{3} - 9 (- 0.60606 \dots)^{2} + 1 = - 3.41884 \dots

f^{^{'}} (u_{1}) = 15 (- 0.60606 \dots)^{2} - 18 (- 0.60606 \dots) = 16.41873 \dots

u_{2} = - 0.39783 \dots

Δ u_{2} = ∣ - 0.39783 \dots - (- 0.60606 \dots) ∣ = 0.20822 \dots

Δ u_{2} = 0.20822 \dots

u_{3} = - 0.32030 \dots : Δ u_{3} = 0.07753 \dots

f (u_{2}) = 5 (- 0.39783 \dots)^{3} - 9 (- 0.39783 \dots)^{2} + 1 = - 0.73926 \dots

f^{^{'}} (u_{2}) = 15 (- 0.39783 \dots)^{2} - 18 (- 0.39783 \dots) = 9.53504 \dots

u_{3} = - 0.32030 \dots

Δ u_{3} = ∣ - 0.32030 \dots - (- 0.39783 \dots) ∣ = 0.07753 \dots

Δ u_{3} = 0.07753 \dots

u_{4} = - 0.30830 \dots : Δ u_{4} = 0.01199 \dots

f (u_{3}) = 5 (- 0.32030 \dots)^{3} - 9 (- 0.32030 \dots)^{2} + 1 = - 0.08764 \dots

f^{^{'}} (u_{3}) = 15 (- 0.32030 \dots)^{2} - 18 (- 0.32030 \dots) = 7.30431 \dots

u_{4} = - 0.30830 \dots

Δ u_{4} = ∣ - 0.30830 \dots - (- 0.32030 \dots) ∣ = 0.01199 \dots

Δ u_{4} = 0.01199 \dots

u_{5} = - 0.30801 \dots : Δ u_{5} = 0.00028 \dots

f (u_{4}) = 5 (- 0.30830 \dots)^{3} - 9 (- 0.30830 \dots)^{2} + 1 = - 0.00197 \dots

f^{^{'}} (u_{4}) = 15 (- 0.30830 \dots)^{2} - 18 (- 0.30830 \dots) = 6.97521 \dots

u_{5} = - 0.30801 \dots

Δ u_{5} = ∣ - 0.30801 \dots - (- 0.30830 \dots) ∣ = 0.00028 \dots

Δ u_{5} = 0.00028 \dots

u_{6} = - 0.30801 \dots : Δ u_{6} = 1.5734 E - 7

f (u_{5}) = 5 (- 0.30801 \dots)^{3} - 9 (- 0.30801 \dots)^{2} + 1 = - 1.09626 E - 6

f^{^{'}} (u_{5}) = 15 (- 0.30801 \dots)^{2} - 18 (- 0.30801 \dots) = 6.96748 \dots

u_{6} = - 0.30801 \dots

Δ u_{6} = ∣ - 0.30801 \dots - (- 0.30801 \dots) ∣ = 1.5734 E - 7

Δ u_{6} = 1.5734 E - 7

u \approx - 0.30801 \dots

Aplicar la división larga

Eq u a t i o n 0 : \frac{5 u ^{3} - 9 u ^{2} + 1}{u + 0.30801 \dots} = 5 u^{2} - 10.54009 \dots u + 3.24655 \dots

5 u^{2} - 10.54009 \dots u + 3.24655 \dots \approx 0

Encontrar una solución para

5 u^{2} - 10.54009 \dots u + 3.24655 \dots = 0

utilizando el método de Newton-Raphson:

u \approx 0.37457 \dots

5 u^{2} - 10.54009 \dots u + 3.24655 \dots = 0

Definición del método de Newton-Raphson

f (u) = 5 u^{2} - 10.54009 \dots u + 3.24655 \dots

Hallar

f^{^{'}} (u) : 10 u - 10.54009 \dots

\frac{d}{d u} (5 u^{2} - 10.54009 \dots u + 3.24655 \dots)

Aplicar la regla de la suma/diferencia:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d u} (5 u^{2}) - \frac{d}{d u} (10.54009 \dots u) + \frac{d}{d u} (3.24655 \dots)

\frac{d}{d u} (5 u^{2}) = 10 u

\frac{d}{d u} (5 u^{2})

Sacar la constante:

(a \cdot f)^{'} = a \cdot f^{'}

= 5 \frac{d}{d u} (u^{2})

Aplicar la regla de la potencia:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= 5 \cdot 2 u^{2 - 1}

Simplificar

= 10 u

\frac{d}{d u} (10.54009 \dots u) = 10.54009 \dots

\frac{d}{d u} (10.54009 \dots u)

Sacar la constante:

(a \cdot f)^{'} = a \cdot f^{'}

= 10.54009 \dots \frac{d u}{d u}

Aplicar la regla de derivación:

\frac{d u}{d u} = 1

= 10.54009 \dots \cdot 1

Simplificar

= 10.54009 \dots

\frac{d}{d u} (3.24655 \dots) = 0

\frac{d}{d u} (3.24655 \dots)

Derivada de una constante:

\frac{d}{d x} (a) = 0

= 0

= 10 u - 10.54009 \dots + 0

Simplificar

= 10 u - 10.54009 \dots

Sea

u_{0} = 0

Calcular

u_{n + 1}

hasta que

Δ u_{n + 1} < 0.000001

u_{1} = 0.30801 \dots : Δ u_{1} = 0.30801 \dots

f (u_{0}) = 5 \cdot 0^{2} - 10.54009 \dots \cdot 0 + 3.24655 \dots = 3.24655 \dots

f^{^{'}} (u_{0}) = 10 \cdot 0 - 10.54009 \dots = - 10.54009 \dots

u_{1} = 0.30801 \dots

Δ u_{1} = ∣ 0.30801 \dots - 0 ∣ = 0.30801 \dots

Δ u_{1} = 0.30801 \dots

u_{2} = 0.37160 \dots : Δ u_{2} = 0.06359 \dots

f (u_{1}) = 5 \cdot 0.30801 \dots^{2} - 10.54009 \dots \cdot 0.30801 \dots + 3.24655 \dots = 0.47437 \dots

f^{^{'}} (u_{1}) = 10 \cdot 0.30801 \dots - 10.54009 \dots = - 7.45990 \dots

u_{2} = 0.37160 \dots

Δ u_{2} = ∣ 0.37160 \dots - 0.30801 \dots ∣ = 0.06359 \dots

Δ u_{2} = 0.06359 \dots

u_{3} = 0.37457 \dots : Δ u_{3} = 0.00296 \dots

f (u_{2}) = 5 \cdot 0.37160 \dots^{2} - 10.54009 \dots \cdot 0.37160 \dots + 3.24655 \dots = 0.02021 \dots

f^{^{'}} (u_{2}) = 10 \cdot 0.37160 \dots - 10.54009 \dots = - 6.82399 \dots

u_{3} = 0.37457 \dots

Δ u_{3} = ∣ 0.37457 \dots - 0.37160 \dots ∣ = 0.00296 \dots

Δ u_{3} = 0.00296 \dots

u_{4} = 0.37457 \dots : Δ u_{4} = 6.46028 E - 6

f (u_{3}) = 5 \cdot 0.37457 \dots^{2} - 10.54009 \dots \cdot 0.37457 \dots + 3.24655 \dots = 0.00004 \dots

f^{^{'}} (u_{3}) = 10 \cdot 0.37457 \dots - 10.54009 \dots = - 6.79437 \dots

u_{4} = 0.37457 \dots

Δ u_{4} = ∣ 0.37457 \dots - 0.37457 \dots ∣ = 6.46028 E - 6

Δ u_{4} = 6.46028 E - 6

u_{5} = 0.37457 \dots : Δ u_{5} = 3.07134 E - 11

f (u_{4}) = 5 \cdot 0.37457 \dots^{2} - 10.54009 \dots \cdot 0.37457 \dots + 3.24655 \dots = 2.08676 E - 10

f^{^{'}} (u_{4}) = 10 \cdot 0.37457 \dots - 10.54009 \dots = - 6.79430 \dots

u_{5} = 0.37457 \dots

Δ u_{5} = ∣ 0.37457 \dots - 0.37457 \dots ∣ = 3.07134 E - 11

Δ u_{5} = 3.07134 E - 11

u \approx 0.37457 \dots

Aplicar la división larga

Eq u a t i o n 0 : \frac{5 u ^{2} - 10.54009 \dots u + 3.24655 \dots}{u - 0.37457 \dots} = 5 u - 8.66720 \dots

5 u - 8.66720 \dots \approx 0

u \approx 1.73344 \dots

Las soluciones son

u \approx - 0.30801 \dots, u \approx 0.37457 \dots, u \approx 1.73344 \dots

u \approx - 0.30801 \dots, u \approx 0.37457 \dots, u \approx 1.73344 \dots

Verificar las soluciones

Encontrar los puntos no definidos (singularidades):

u = 0

Tomar el(los) denominador(es) de

- 8 + \frac{1 - u ^{2}}{u ^{2}} + 5 u

y comparar con cero

Resolver

u^{2} = 0 : u = 0

u^{2} = 0

Aplicar la regla

x^{n} = 0 \Rightarrow x = 0

u = 0

Los siguientes puntos no están definidos

u = 0

Combinar los puntos no definidos con las soluciones:

u \approx - 0.30801 \dots, u \approx 0.37457 \dots, u \approx 1.73344 \dots

Sustituir en la ecuación

u = cos (x)

cos (x) \approx - 0.30801 \dots, cos (x) \approx 0.37457 \dots, cos (x) \approx 1.73344 \dots

cos (x) \approx - 0.30801 \dots, cos (x) \approx 0.37457 \dots, cos (x) \approx 1.73344 \dots

cos (x) = - 0.30801 \dots : x = arccos (- 0.30801 \dots) + 2 πn, x = - arccos (- 0.30801 \dots) + 2 πn

cos (x) = - 0.30801 \dots

Aplicar propiedades trigonométricas inversas

cos (x) = - 0.30801 \dots

Soluciones generales para

cos (x) = - 0.30801 \dots

cos (x) = - a \Rightarrow x = arccos (- a) + 2 πn, x = - arccos (- a) + 2 πn

x = arccos (- 0.30801 \dots) + 2 πn, x = - arccos (- 0.30801 \dots) + 2 πn

x = arccos (- 0.30801 \dots) + 2 πn, x = - arccos (- 0.30801 \dots) + 2 πn

cos (x) = 0.37457 \dots : x = arccos (0.37457 \dots) + 2 πn, x = 2 π - arccos (0.37457 \dots) + 2 πn

cos (x) = 0.37457 \dots

Aplicar propiedades trigonométricas inversas

cos (x) = 0.37457 \dots

Soluciones generales para

cos (x) = 0.37457 \dots

cos (x) = a \Rightarrow x = arccos (a) + 2 πn, x = 2 π - arccos (a) + 2 πn

x = arccos (0.37457 \dots) + 2 πn, x = 2 π - arccos (0.37457 \dots) + 2 πn

x = arccos (0.37457 \dots) + 2 πn, x = 2 π - arccos (0.37457 \dots) + 2 πn

cos (x) = 1.73344 \dots :

Sin solución

cos (x) = 1.73344 \dots

- 1 \leq cos (x) \leq 1

Sin soluci \overset{o}{ˊ} n

Combinar toda las soluciones

x = arccos (- 0.30801 \dots) + 2 πn, x = - arccos (- 0.30801 \dots) + 2 πn, x = arccos (0.37457 \dots) + 2 πn, x = 2 π - arccos (0.37457 \dots) + 2 πn

Mostrar soluciones en forma decimal

x = 1.88390 \dots + 2 πn, x = - 1.88390 \dots + 2 πn, x = 1.18685 \dots + 2 πn, x = 2 π - 1.18685 \dots + 2 πn

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