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受欢迎的三角函数 >

2sin^2(3x)-3cos(3x)+1=0,0<= x<= 180

解答

2 sin^{2} (3 x) - 3 cos (3 x) + 1 = 0, 0^{\circ} \leq x \leq 18 0^{\circ}

解答

x = \frac{0.81462 \dots}{3}, x = \frac{36 0 ^{\circ} - 0.81462 \dots}{3}, x = \frac{0.81462 \dots + 36 0 ^{\circ}}{3}

+1

弧度

x = \frac{0.81462 \dots}{3}, x = \frac{2 π - 0.81462 \dots}{3}, x = \frac{0.81462 \dots + 2 π}{3}

求解步骤

2 sin^{2} (3 x) - 3 cos (3 x) + 1 = 0, 0^{\circ} \leq x \leq 18 0^{\circ}

使用三角恒等式改写

1 + 2 sin^{2} (3 x) - 3 cos (3 x)

使用毕达哥拉斯恒等式:

cos^{2} (x) + sin^{2} (x) = 1

sin^{2} (x) = 1 - cos^{2} (x)

= 1 + 2 (1 - cos^{2} (3 x)) - 3 cos (3 x)

化简

1 + 2 (1 - cos^{2} (3 x)) - 3 cos (3 x) : - 2 cos^{2} (3 x) - 3 cos (3 x) + 3

1 + 2 (1 - cos^{2} (3 x)) - 3 cos (3 x)

乘开

2 (1 - cos^{2} (3 x)) : 2 - 2 cos^{2} (3 x)

2 (1 - cos^{2} (3 x))

使用分配律:

a (b - c) = ab - a c

a = 2, b = 1, c = cos^{2} (3 x)

= 2 \cdot 1 - 2 cos^{2} (3 x)

数字相乘:

2 \cdot 1 = 2

= 2 - 2 cos^{2} (3 x)

= 1 + 2 - 2 cos^{2} (3 x) - 3 cos (3 x)

数字相加:

1 + 2 = 3

= - 2 cos^{2} (3 x) - 3 cos (3 x) + 3

= - 2 cos^{2} (3 x) - 3 cos (3 x) + 3

3 - 2 cos^{2} (3 x) - 3 cos (3 x) = 0

用替代法求解

3 - 2 cos^{2} (3 x) - 3 cos (3 x) = 0

令

: cos (3 x) = u

3 - 2 u^{2} - 3 u = 0

3 - 2 u^{2} - 3 u = 0 : u = - \frac{3 + 33}{4}, u = \frac{33 - 3}{4}

3 - 2 u^{2} - 3 u = 0

改写成标准形式

a x^{2} + b x + c = 0

- 2 u^{2} - 3 u + 3 = 0

使用求根公式求解

- 2 u^{2} - 3 u + 3 = 0

二次方程求根公式:

若

a = - 2, b = - 3, c = 3

u_{1, 2} = \frac{- ( - 3 ) \pm ( - 3 ) ^{2} - 4 ( - 2 ) \cdot 3}{2 ( - 2 )}

u_{1, 2} = \frac{- ( - 3 ) \pm ( - 3 ) ^{2} - 4 ( - 2 ) \cdot 3}{2 ( - 2 )}

(- 3)^{2} - 4 (- 2) \cdot 3 = 33

(- 3)^{2} - 4 (- 2) \cdot 3

使用法则

- (- a) = a

= (- 3)^{2} + 4 \cdot 2 \cdot 3

使用指数法则:

(- a)^{n} = a^{n},

若

n

是偶数

(- 3)^{2} = 3^{2}

= 3^{2} + 4 \cdot 2 \cdot 3

数字相乘:

4 \cdot 2 \cdot 3 = 24

= 3^{2} + 24

3^{2} = 9

= 9 + 24

数字相加:

9 + 24 = 33

= 33

u_{1, 2} = \frac{- ( - 3 ) \pm 33}{2 ( - 2 )}

将解分隔开

u_{1} = \frac{- ( - 3 ) + 33}{2 ( - 2 )}, u_{2} = \frac{- ( - 3 ) - 33}{2 ( - 2 )}

u = \frac{- ( - 3 ) + 33}{2 ( - 2 )} : - \frac{3 + 33}{4}

\frac{- ( - 3 ) + 33}{2 ( - 2 )}

去除括号:

(- a) = - a, - (- a) = a

= \frac{3 + 33}{- 2 \cdot 2}

数字相乘:

2 \cdot 2 = 4

= \frac{3 + 33}{- 4}

使用分式法则:

\frac{a}{- b} = - \frac{a}{b}

= - \frac{3 + 33}{4}

u = \frac{- ( - 3 ) - 33}{2 ( - 2 )} : \frac{33 - 3}{4}

\frac{- ( - 3 ) - 33}{2 ( - 2 )}

去除括号:

(- a) = - a, - (- a) = a

= \frac{3 - 33}{- 2 \cdot 2}

数字相乘:

2 \cdot 2 = 4

= \frac{3 - 33}{- 4}

使用分式法则:

\frac{- a}{- b} = \frac{a}{b}

3 - 33 = - (33 - 3)

= \frac{33 - 3}{4}

二次方程组的解是:

u = - \frac{3 + 33}{4}, u = \frac{33 - 3}{4}

u = cos (3 x)

代回

cos (3 x) = - \frac{3 + 33}{4}, cos (3 x) = \frac{33 - 3}{4}

cos (3 x) = - \frac{3 + 33}{4}, cos (3 x) = \frac{33 - 3}{4}

cos (3 x) = - \frac{3 + 33}{4}, 0 \leq x \leq 18 0^{\circ} :

无解

cos (3 x) = - \frac{3 + 33}{4}, 0 \leq x \leq 18 0^{\circ}

- 1 \leq cos (x) \leq 1

无解

cos (3 x) = \frac{33 - 3}{4}, 0 \leq x \leq 18 0^{\circ} : x = \frac{arccos ( \frac{33 - 3}{4} )}{3}, x = \frac{36 0 ^{\circ} - arccos ( \frac{33 - 3}{4} )}{3}, x = \frac{arccos ( \frac{33 - 3}{4} ) + 36 0 ^{\circ}}{3}

cos (3 x) = \frac{33 - 3}{4}, 0 \leq x \leq 18 0^{\circ}

使用反三角函数性质

cos (3 x) = \frac{33 - 3}{4}

cos (3 x) = \frac{33 - 3}{4}

的通解

cos (x) = a \Rightarrow x = arccos (a) + 36 0^{\circ} n, x = 36 0^{\circ} - arccos (a) + 36 0^{\circ} n

3 x = arccos (\frac{33 - 3}{4}) + 36 0^{\circ} n, 3 x = 36 0^{\circ} - arccos (\frac{33 - 3}{4}) + 36 0^{\circ} n

3 x = arccos (\frac{33 - 3}{4}) + 36 0^{\circ} n, 3 x = 36 0^{\circ} - arccos (\frac{33 - 3}{4}) + 36 0^{\circ} n

解

3 x = arccos (\frac{33 - 3}{4}) + 36 0^{\circ} n : x = \frac{arccos ( \frac{33 - 3}{4} )}{3} + \frac{36 0 ^{\circ} n}{3}

3 x = arccos (\frac{33 - 3}{4}) + 36 0^{\circ} n

两边除以

3

3 x = arccos (\frac{33 - 3}{4}) + 36 0^{\circ} n

两边除以

3

\frac{3 x}{3} = \frac{arccos ( \frac{33 - 3}{4} )}{3} + \frac{36 0 ^{\circ} n}{3}

化简

x = \frac{arccos ( \frac{33 - 3}{4} )}{3} + \frac{36 0 ^{\circ} n}{3}

x = \frac{arccos ( \frac{33 - 3}{4} )}{3} + \frac{36 0 ^{\circ} n}{3}

解

3 x = 36 0^{\circ} - arccos (\frac{33 - 3}{4}) + 36 0^{\circ} n : x = 12 0^{\circ} - \frac{arccos ( \frac{33 - 3}{4} )}{3} + \frac{36 0 ^{\circ} n}{3}

3 x = 36 0^{\circ} - arccos (\frac{33 - 3}{4}) + 36 0^{\circ} n

两边除以

3

3 x = 36 0^{\circ} - arccos (\frac{33 - 3}{4}) + 36 0^{\circ} n

两边除以

3

\frac{3 x}{3} = 12 0^{\circ} - \frac{arccos ( \frac{33 - 3}{4} )}{3} + \frac{36 0 ^{\circ} n}{3}

化简

x = 12 0^{\circ} - \frac{arccos ( \frac{33 - 3}{4} )}{3} + \frac{36 0 ^{\circ} n}{3}

x = 12 0^{\circ} - \frac{arccos ( \frac{33 - 3}{4} )}{3} + \frac{36 0 ^{\circ} n}{3}

x = \frac{arccos ( \frac{33 - 3}{4} )}{3} + \frac{36 0 ^{\circ} n}{3}, x = 12 0^{\circ} - \frac{arccos ( \frac{33 - 3}{4} )}{3} + \frac{36 0 ^{\circ} n}{3}

在

0 \leq x \leq 18 0^{\circ}

范围内的解

x = \frac{arccos ( \frac{33 - 3}{4} )}{3}, x = \frac{36 0 ^{\circ} - arccos ( \frac{33 - 3}{4} )}{3}, x = \frac{arccos ( \frac{33 - 3}{4} ) + 36 0 ^{\circ}}{3}

合并所有解

x = \frac{arccos ( \frac{33 - 3}{4} )}{3}, x = \frac{36 0 ^{\circ} - arccos ( \frac{33 - 3}{4} )}{3}, x = \frac{arccos ( \frac{33 - 3}{4} ) + 36 0 ^{\circ}}{3}

以小数形式表示解

x = \frac{0.81462 \dots}{3}, x = \frac{36 0 ^{\circ} - 0.81462 \dots}{3}, x = \frac{0.81462 \dots + 36 0 ^{\circ}}{3}

作图

流行的例子

2sin(x/2)=1-cos(x)

2 sin (\frac{x}{2}) = 1 - cos (x)

sin(x)=(-sin(2x))/2

sin (x) = \frac{- sin ( 2 x )}{2}

12sin(A)+4=4sin(A)+4

12 sin (A) + 4 = 4 sin (A) + 4

2sin^2(x)=3-3cos(x)

2 sin^{2} (x) = 3 - 3 cos (x)

cos(x)+sin(x)tan(x)=1

cos (x) + sin (x) tan (x) = 1