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受欢迎的三角函数 >

3cos(x)+sec(145)=1

解答

3 cos (x) + sec (14 5^{\circ}) = 1

解答

x = 0.7373420134 + 36 0^{\circ} n, x = 36 0^{\circ} - 0.7373420134 + 36 0^{\circ} n

+1

弧度

x = 0.7373420134 + 2 πn, x = 2 π - 0.7373420134 + 2 πn

求解步骤

3 cos (x) + sec (14 5^{\circ}) = 1

将

sec (14 5^{\circ})

到右边

3 cos (x) + sec (14 5^{\circ}) = 1

两边减去

sec (14 5^{\circ})

3 cos (x) + sec (14 5^{\circ}) - sec (14 5^{\circ}) = 1 - sec (14 5^{\circ})

化简

3 cos (x) = 1 - sec (14 5^{\circ})

3 cos (x) = 1 - sec (14 5^{\circ})

两边除以

3

3 cos (x) = 1 - sec (14 5^{\circ})

两边除以

3

\frac{3 cos ( x )}{3} = \frac{1}{3} - \frac{sec ( 14 5 ^{\circ} )}{3}

化简

\frac{3 cos ( x )}{3} = \frac{1}{3} - \frac{sec ( 14 5 ^{\circ} )}{3}

化简

\frac{3 cos ( x )}{3} : cos (x)

\frac{3 cos ( x )}{3}

数字相除:

\frac{3}{3} = 1

= cos (x)

化简

\frac{1}{3} - \frac{sec ( 14 5 ^{\circ} )}{3} : \frac{1 - sec ( 14 5 ^{\circ} )}{3}

\frac{1}{3} - \frac{sec ( 14 5 ^{\circ} )}{3}

使用法则

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

= \frac{1 - sec ( 14 5 ^{\circ} )}{3}

cos (x) = \frac{1 - sec ( 14 5 ^{\circ} )}{3}

cos (x) = \frac{1 - sec ( 14 5 ^{\circ} )}{3}

cos (x) = \frac{1 - sec ( 14 5 ^{\circ} )}{3}

使用反三角函数性质

cos (x) = \frac{1 - sec ( 14 5 ^{\circ} )}{3}

cos (x) = \frac{1 - sec ( 14 5 ^{\circ} )}{3}

的通解

cos (x) = a \Rightarrow x = arccos (a) + 36 0^{\circ} n, x = 36 0^{\circ} - arccos (a) + 36 0^{\circ} n

x = arccos (\frac{1 - sec ( 14 5 ^{\circ} )}{3}) + 36 0^{\circ} n, x = 36 0^{\circ} - arccos (\frac{1 - sec ( 14 5 ^{\circ} )}{3}) + 36 0^{\circ} n

x = arccos (\frac{1 - sec ( 14 5 ^{\circ} )}{3}) + 36 0^{\circ} n, x = 36 0^{\circ} - arccos (\frac{1 - sec ( 14 5 ^{\circ} )}{3}) + 36 0^{\circ} n

以小数形式表示解

x = 0.7373420134 + 36 0^{\circ} n, x = 36 0^{\circ} - 0.7373420134 + 36 0^{\circ} n

作图

流行的例子

sec^2(x)+3tan^2(x)=13

sec^{2} (x) + 3 tan^{2} (x) = 13

1609.3=(1.133^2)/((9.8)tan(θ))

1609.3 = \frac{1.13 3 ^{2}}{( 9.8 ) tan ( θ )}

2 sec^{2} (2 x) = 0

cos(x)=((-3)/4)

cos (x) = (\frac{- 3}{4})

4(cos(x))^2=5-4sin(x)

4 (cos (x))^{2} = 5 - 4 sin (x)