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人気のある三角関数 >

sin(b)=12((sin(42))/(22))

解

sin (b) = 12 (\frac{sin ( 4 2 ^{\circ} )}{22})

解

b = 0.37361 \dots + 36 0^{\circ} n, b = 18 0^{\circ} - 0.37361 \dots + 36 0^{\circ} n

+1

ラジアン

b = 0.37361 \dots + 2 πn, b = π - 0.37361 \dots + 2 πn

解答ステップ

sin (b) = 12 (\frac{sin ( 4 2 ^{\circ} )}{22})

簡素化

12 \cdot \frac{sin ( 4 2 ^{\circ} )}{22} : \frac{6 sin ( 4 2 ^{\circ} )}{11}

12 \cdot \frac{sin ( 4 2 ^{\circ} )}{22}

分数を乗じる:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{sin ( 4 2 ^{\circ} ) \cdot 12}{22}

共通因数を約分する:

2

= \frac{6 sin ( 4 2 ^{\circ} )}{11}

三角関数の逆数プロパティを適用する

sin (b) = \frac{6 sin ( 4 2 ^{\circ} )}{11}

以下の一般解

sin (b) = \frac{6 sin ( 4 2 ^{\circ} )}{11}

sin (x) = a \Rightarrow x = arcsin (a) + 36 0^{\circ} n, x = 18 0^{\circ} - arcsin (a) + 36 0^{\circ} n

b = arcsin (\frac{6 sin ( 4 2 ^{\circ} )}{11}) + 36 0^{\circ} n, b = 18 0^{\circ} - arcsin (\frac{6 sin ( 4 2 ^{\circ} )}{11}) + 36 0^{\circ} n

b = arcsin (\frac{6 sin ( 4 2 ^{\circ} )}{11}) + 36 0^{\circ} n, b = 18 0^{\circ} - arcsin (\frac{6 sin ( 4 2 ^{\circ} )}{11}) + 36 0^{\circ} n

10進法形式で解を証明する

b = 0.37361 \dots + 36 0^{\circ} n, b = 18 0^{\circ} - 0.37361 \dots + 36 0^{\circ} n

グラフ

人気の例

arctan(sqrt(3/1))=tan(θ)

arctan (\frac{3}{1}) = tan (θ)

2sin^2(x)-5cos(x)+5=0

2 sin^{2} (x) - 5 cos (x) + 5 = 0

tan (x) = \frac{20}{40}

sqrt(2)sin(x+pi/4)=0

2 sin (x + \frac{π}{4}) = 0

sin(x)=(2(5.5*10^{-7}))/(3.36*10^{-5)}

sin (x) = \frac{2 ( 5.5 \cdot 1 0 ^{- 7} )}{3.36 \cdot 1 0 ^{- 5}}