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Popular >

6cos^2(A)-5cos(A)+1=0

Solución

6 cos^{2} (A) - 5 cos (A) + 1 = 0

Solución

A = \frac{π}{3} + 2 πn, A = \frac{5 π}{3} + 2 πn, A = 1.23095 \dots + 2 πn, A = 2 π - 1.23095 \dots + 2 πn

+1

Pasos de solución

6 cos^{2} (A) - 5 cos (A) + 1 = 0

Usando el método de sustitución

cos (A) = \frac{1}{2}, cos (A) = \frac{1}{3}

cos (A) = \frac{1}{2} : A = \frac{π}{3} + 2 πn, A = \frac{5 π}{3} + 2 πn

cos (A) = \frac{1}{3} : A = arccos (\frac{1}{3}) + 2 πn, A = 2 π - arccos (\frac{1}{3}) + 2 πn

Combinar toda las soluciones

A = \frac{π}{3} + 2 πn, A = \frac{5 π}{3} + 2 πn, A = arccos (\frac{1}{3}) + 2 πn, A = 2 π - arccos (\frac{1}{3}) + 2 πn

Mostrar soluciones en forma decimal

A = \frac{π}{3} + 2 πn, A = \frac{5 π}{3} + 2 πn, A = 1.23095 \dots + 2 πn, A = 2 π - 1.23095 \dots + 2 πn

Ejemplos populares

cos(x)tan^2(x)-3cos(x)=0

cos (x) tan^{2} (x) - 3 cos (x) = 0

2sin(x)+3cot(x)-3csc(x)=0

2 sin (x) + 3 cot (x) - 3 csc (x) = 0

cos^2(θ)-3cos(θ)+2=0

cos^{2} (θ) - 3 cos (θ) + 2 = 0

cos(2x-pi/6)=-1/2 , pi/2 <= x<pi

cos (2 x - \frac{π}{6}) = - \frac{1}{2}, \frac{π}{2} \leq x < π

((sin(x)))/((4.2))=((sin(95)))/((10.26))

\frac{( sin ( x ) )}{( 4.2 )} = \frac{( sin ( 9 5 ^{\circ} ) )}{( 10.26 )}