ja

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

人気のある三角関数 >

solvefor c,e=r(sec(c/2)-1)

解

解く

c, e = r (sec (\frac{c}{2}) - 1)

解

c = 2 arcsec (\frac{e}{r} + 1) + 4 πn, c = - 2 arcsec (\frac{e}{r} + 1) + 4 πn

解答ステップ

e = r (sec (\frac{c}{2}) - 1)

辺を交換する

r (sec (\frac{c}{2}) - 1) = e

以下で両辺を割る

r; r \neq = 0

r (sec (\frac{c}{2}) - 1) = e

以下で両辺を割る

r; r \neq = 0

\frac{r ( sec ( \frac{c}{2} ) - 1 )}{r} = \frac{e}{r}; r \neq = 0

簡素化

sec (\frac{c}{2}) - 1 = \frac{e}{r}; r \neq = 0

sec (\frac{c}{2}) - 1 = \frac{e}{r}; r \neq = 0

1

を右側に移動します

sec (\frac{c}{2}) - 1 = \frac{e}{r}; r \neq = 0

両辺に

1

を足す

sec (\frac{c}{2}) - 1 + 1 = \frac{e}{r} + 1; r \neq = 0

簡素化

sec (\frac{c}{2}) = \frac{e}{r} + 1; r \neq = 0

sec (\frac{c}{2}) = \frac{e}{r} + 1; r \neq = 0

三角関数の逆数プロパティを適用する

sec (\frac{c}{2}) = \frac{e}{r} + 1

以下の一般解

sec (\frac{c}{2}) = \frac{e}{r} + 1

sec (x) = a \Rightarrow x = arcsec (a) + 2 πn, x = - arcsec (a) + 2 πn

\frac{c}{2} = arcsec (\frac{e}{r} + 1) + 2 πn, \frac{c}{2} = - arcsec (\frac{e}{r} + 1) + 2 πn

\frac{c}{2} = arcsec (\frac{e}{r} + 1) + 2 πn, \frac{c}{2} = - arcsec (\frac{e}{r} + 1) + 2 πn

解く

\frac{c}{2} = arcsec (\frac{e}{r} + 1) + 2 πn : c = 2 arcsec (\frac{e}{r} + 1) + 4 πn

\frac{c}{2} = arcsec (\frac{e}{r} + 1) + 2 πn

以下で両辺を乗じる:

2

\frac{c}{2} = arcsec (\frac{e}{r} + 1) + 2 πn

以下で両辺を乗じる:

2

\frac{2 c}{2} = 2 arcsec (\frac{e}{r} + 1) + 2 \cdot 2 πn

簡素化

\frac{2 c}{2} = 2 arcsec (\frac{e}{r} + 1) + 2 \cdot 2 πn

簡素化

\frac{2 c}{2} : c

\frac{2 c}{2}

数を割る:

\frac{2}{2} = 1

= c

簡素化

2 arcsec (\frac{e}{r} + 1) + 2 \cdot 2 πn : 2 arcsec (\frac{e}{r} + 1) + 4 πn

2 arcsec (\frac{e}{r} + 1) + 2 \cdot 2 πn

数を乗じる:

2 \cdot 2 = 4

= 2 arcsec (\frac{e}{r} + 1) + 4 πn

c = 2 arcsec (\frac{e}{r} + 1) + 4 πn

c = 2 arcsec (\frac{e}{r} + 1) + 4 πn

c = 2 arcsec (\frac{e}{r} + 1) + 4 πn

解く

\frac{c}{2} = - arcsec (\frac{e}{r} + 1) + 2 πn : c = - 2 arcsec (\frac{e}{r} + 1) + 4 πn

\frac{c}{2} = - arcsec (\frac{e}{r} + 1) + 2 πn

以下で両辺を乗じる:

2

\frac{c}{2} = - arcsec (\frac{e}{r} + 1) + 2 πn

以下で両辺を乗じる:

2

\frac{2 c}{2} = - 2 arcsec (\frac{e}{r} + 1) + 2 \cdot 2 πn

簡素化

\frac{2 c}{2} = - 2 arcsec (\frac{e}{r} + 1) + 2 \cdot 2 πn

簡素化

\frac{2 c}{2} : c

\frac{2 c}{2}

数を割る:

\frac{2}{2} = 1

= c

簡素化

- 2 arcsec (\frac{e}{r} + 1) + 2 \cdot 2 πn : - 2 arcsec (\frac{e}{r} + 1) + 4 πn

- 2 arcsec (\frac{e}{r} + 1) + 2 \cdot 2 πn

数を乗じる:

2 \cdot 2 = 4

= - 2 arcsec (\frac{e}{r} + 1) + 4 πn

c = - 2 arcsec (\frac{e}{r} + 1) + 4 πn

c = - 2 arcsec (\frac{e}{r} + 1) + 4 πn

c = - 2 arcsec (\frac{e}{r} + 1) + 4 πn

c = 2 arcsec (\frac{e}{r} + 1) + 4 πn, c = - 2 arcsec (\frac{e}{r} + 1) + 4 πn

グラフ

人気の例

arctan(x/3)+arctan(x/2)=arctan(x)

arctan (\frac{x}{3}) + arctan (\frac{x}{2}) = arctan (x)

solvefor w,y=arctan(1+4w)

so l v e f or w, y = arctan (1 + 4 w)

cos (8 x) = 1

cos^4(a)=8cos^4(a)-8cos^2(a)+1

cos^{4} (a) = 8 cos^{4} (a) - 8 cos^{2} (a) + 1

sin^2(a)-4sin(a)+3=0

sin^{2} (a) - 4 sin (a) + 3 = 0