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受欢迎的三角函数 >

2sqrt(3)*sin(4x+60^0)-3=0

解答

23 \cdot sin (4 x + 6 0^{0}) - 3 = 0

解答

x = - \frac{1}{4} + \frac{π}{12} + \frac{πn}{2}, x = - \frac{1}{4} + \frac{π}{6} + \frac{πn}{2}

+1

度数

x = 0.67605 \dots^{\circ} + 9 0^{\circ} n, x = 15.67605 \dots^{\circ} + 9 0^{\circ} n

求解步骤

23 sin (4 x + 6 0^{0}) - 3 = 0

将

3

到右边

23 sin (4 x + 6 0^{0}) - 3 = 0

两边加上

3

23 sin (4 x + 6 0^{0}) - 3 + 3 = 0 + 3

化简

23 sin (4 x + 6 0^{0}) = 3

23 sin (4 x + 6 0^{0}) = 3

两边除以

23

23 sin (4 x + 6 0^{0}) = 3

两边除以

23

\frac{2 3 sin ( 4 x + 6 0 ^{0} )}{2 3} = \frac{3}{2 3}

化简

\frac{2 3 sin ( 4 x + 6 0 ^{0} )}{2 3} = \frac{3}{2 3}

化简

\frac{2 3 sin ( 4 x + 6 0 ^{0} )}{2 3} : sin (4 x + 6 0^{0})

\frac{2 3 sin ( 4 x + 6 0 ^{0} )}{2 3}

数字相除:

\frac{2}{2} = 1

= \frac{3 sin ( 4 x + 6 0 ^{0} )}{3}

约分:

3

= sin (4 x + 6 0^{0})

化简

\frac{3}{2 3} : \frac{3}{2}

\frac{3}{2 3}

使用根式运算法则:

n a = a^{\frac{1}{n}}

3 = 3^{\frac{1}{2}}

= \frac{3}{2 \cdot 3 ^{\frac{1}{2}}}

使用指数法则:

\frac{x ^{a}}{x ^{b}} = x^{a - b}

\frac{3 ^{1}}{3 ^{\frac{1}{2}}} = 3^{1 - \frac{1}{2}}

= \frac{3 ^{1 - \frac{1}{2}}}{2}

数字相减:

1 - \frac{1}{2} = \frac{1}{2}

= \frac{3 ^{\frac{1}{2}}}{2}

使用根式运算法则:

a^{\frac{1}{n}} = n a

3^{\frac{1}{2}} = 3

= \frac{3}{2}

sin (4 x + 6 0^{0}) = \frac{3}{2}

sin (4 x + 6 0^{0}) = \frac{3}{2}

sin (4 x + 6 0^{0}) = \frac{3}{2}

sin (4 x + 6 0^{0}) = \frac{3}{2}

的通解

sin (x)

周期表（周期为

2 πn

"）：

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} sin (x) 0 \frac{1}{2} \frac{2}{2} \frac{3}{2} 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} x π \frac{7 π}{6} \frac{5 π}{4} \frac{4 π}{3} \frac{3 π}{2} \frac{5 π}{3} \frac{7 π}{4} \frac{11 π}{6} sin (x) 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2}

4 x + 6 0^{0} = \frac{π}{3} + 2 πn, 4 x + 6 0^{0} = \frac{2 π}{3} + 2 πn

4 x + 6 0^{0} = \frac{π}{3} + 2 πn, 4 x + 6 0^{0} = \frac{2 π}{3} + 2 πn

解

4 x + 6 0^{0} = \frac{π}{3} + 2 πn : x = - \frac{1}{4} + \frac{π}{12} + \frac{πn}{2}

4 x + 6 0^{0} = \frac{π}{3} + 2 πn

使用法则

a^{0} = 1, a \neq = 0

6 0^{0} = 1

4 x + 1 = \frac{π}{3} + 2 πn

将

1

到右边

4 x + 1 = \frac{π}{3} + 2 πn

两边减去

1

4 x + 1 - 1 = \frac{π}{3} + 2 πn - 1

化简

4 x = \frac{π}{3} + 2 πn - 1

4 x = \frac{π}{3} + 2 πn - 1

两边除以

4

4 x = \frac{π}{3} + 2 πn - 1

两边除以

4

\frac{4 x}{4} = \frac{\frac{π}{3}}{4} + \frac{2 πn}{4} - \frac{1}{4}

化简

\frac{4 x}{4} = \frac{\frac{π}{3}}{4} + \frac{2 πn}{4} - \frac{1}{4}

化简

\frac{4 x}{4} : x

\frac{4 x}{4}

数字相除:

\frac{4}{4} = 1

= x

化简

\frac{\frac{π}{3}}{4} + \frac{2 πn}{4} - \frac{1}{4} : - \frac{1}{4} + \frac{π}{12} + \frac{πn}{2}

\frac{\frac{π}{3}}{4} + \frac{2 πn}{4} - \frac{1}{4}

对同类项分组

= - \frac{1}{4} + \frac{2 πn}{4} + \frac{\frac{π}{3}}{4}

\frac{2 πn}{4} = \frac{πn}{2}

\frac{2 πn}{4}

约分:

2

= \frac{πn}{2}

\frac{\frac{π}{3}}{4} = \frac{π}{12}

\frac{\frac{π}{3}}{4}

使用分式法则:

\frac{\frac{b}{c}}{a} = \frac{b}{c \cdot a}

= \frac{π}{3 \cdot 4}

数字相乘:

3 \cdot 4 = 12

= \frac{π}{12}

= - \frac{1}{4} + \frac{πn}{2} + \frac{π}{12}

对同类项分组

= - \frac{1}{4} + \frac{π}{12} + \frac{πn}{2}

x = - \frac{1}{4} + \frac{π}{12} + \frac{πn}{2}

x = - \frac{1}{4} + \frac{π}{12} + \frac{πn}{2}

x = - \frac{1}{4} + \frac{π}{12} + \frac{πn}{2}

解

4 x + 6 0^{0} = \frac{2 π}{3} + 2 πn : x = - \frac{1}{4} + \frac{π}{6} + \frac{πn}{2}

4 x + 6 0^{0} = \frac{2 π}{3} + 2 πn

使用法则

a^{0} = 1, a \neq = 0

6 0^{0} = 1

4 x + 1 = \frac{2 π}{3} + 2 πn

将

1

到右边

4 x + 1 = \frac{2 π}{3} + 2 πn

两边减去

1

4 x + 1 - 1 = \frac{2 π}{3} + 2 πn - 1

化简

4 x = \frac{2 π}{3} + 2 πn - 1

4 x = \frac{2 π}{3} + 2 πn - 1

两边除以

4

4 x = \frac{2 π}{3} + 2 πn - 1

两边除以

4

\frac{4 x}{4} = \frac{\frac{2 π}{3}}{4} + \frac{2 πn}{4} - \frac{1}{4}

化简

\frac{4 x}{4} = \frac{\frac{2 π}{3}}{4} + \frac{2 πn}{4} - \frac{1}{4}

化简

\frac{4 x}{4} : x

\frac{4 x}{4}

数字相除:

\frac{4}{4} = 1

= x

化简

\frac{\frac{2 π}{3}}{4} + \frac{2 πn}{4} - \frac{1}{4} : - \frac{1}{4} + \frac{π}{6} + \frac{πn}{2}

\frac{\frac{2 π}{3}}{4} + \frac{2 πn}{4} - \frac{1}{4}

对同类项分组

= - \frac{1}{4} + \frac{2 πn}{4} + \frac{\frac{2 π}{3}}{4}

\frac{2 πn}{4} = \frac{πn}{2}

\frac{2 πn}{4}

约分:

2

= \frac{πn}{2}

\frac{\frac{2 π}{3}}{4} = \frac{π}{6}

\frac{\frac{2 π}{3}}{4}

使用分式法则:

\frac{\frac{b}{c}}{a} = \frac{b}{c \cdot a}

= \frac{2 π}{3 \cdot 4}

数字相乘:

3 \cdot 4 = 12

= \frac{2 π}{12}

约分:

2

= \frac{π}{6}

= - \frac{1}{4} + \frac{πn}{2} + \frac{π}{6}

对同类项分组

= - \frac{1}{4} + \frac{π}{6} + \frac{πn}{2}

x = - \frac{1}{4} + \frac{π}{6} + \frac{πn}{2}

x = - \frac{1}{4} + \frac{π}{6} + \frac{πn}{2}

x = - \frac{1}{4} + \frac{π}{6} + \frac{πn}{2}

x = - \frac{1}{4} + \frac{π}{12} + \frac{πn}{2}, x = - \frac{1}{4} + \frac{π}{6} + \frac{πn}{2}

作图

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