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人気のある三角関数 >

solvefor x,cot^2(x)= 1/3

解

解く

x, cot^{2} (x) = \frac{1}{3}

解

x = 1.04719 \dots + πn, x = 2.09439 \dots + πn

+1

度

x = 6 0^{\circ} + 18 0^{\circ} n, x = 12 0^{\circ} + 18 0^{\circ} n

解答ステップ

cot^{2} (x) = \frac{1}{3}

置換で解く

cot^{2} (x) = \frac{1}{3}

仮定:

cot (x) = u

u^{2} = \frac{1}{3}

u^{2} = \frac{1}{3} : u = \frac{1}{3}, u = - \frac{1}{3}

u^{2} = \frac{1}{3}

x^{2} = f (a)

の場合, 解は

x = f (a), - f (a)

u = \frac{1}{3}, u = - \frac{1}{3}

代用を戻す

u = cot (x)

cot (x) = \frac{1}{3}, cot (x) = - \frac{1}{3}

cot (x) = \frac{1}{3}, cot (x) = - \frac{1}{3}

cot (x) = \frac{1}{3} : x = arccot (\frac{1}{3}) + πn

cot (x) = \frac{1}{3}

三角関数の逆数プロパティを適用する

cot (x) = \frac{1}{3}

以下の一般解

cot (x) = \frac{1}{3}

cot (x) = a \Rightarrow x = arccot (a) + πn

x = arccot (\frac{1}{3}) + πn

x = arccot (\frac{1}{3}) + πn

cot (x) = - \frac{1}{3} : x = arccot (- \frac{1}{3}) + πn

cot (x) = - \frac{1}{3}

三角関数の逆数プロパティを適用する

cot (x) = - \frac{1}{3}

以下の一般解

cot (x) = - \frac{1}{3}

cot (x) = - a \Rightarrow x = arccot (- a) + πn

x = arccot (- \frac{1}{3}) + πn

x = arccot (- \frac{1}{3}) + πn

すべての解を組み合わせる

x = arccot (\frac{1}{3}) + πn, x = arccot (- \frac{1}{3}) + πn

10進法形式で解を証明する

x = 1.04719 \dots + πn, x = 2.09439 \dots + πn

グラフ

人気の例

2+cos^2(x)=-5sin(x)

2 + cos^{2} (x) = - 5 sin (x)

tan^5(x)tan^2(x)=1

tan^{5} (x) tan^{2} (x) = 1

(sin^2(a)+1)/((1+tan^2(a)))=1

\frac{sin ^{2} ( a ) + 1}{( 1 + tan ^{2} ( a ) )} = 1

tan(a)= 5/9 ,b=6

tan (a) = \frac{5}{9}, b = 6

sin^3(x)sin^2(x)sin(x)=0

sin^{3} (x) sin^{2} (x) sin (x) = 0