The sum of 3 consecutive even numbers is 403.What is the largest of the numbers?

解

T h e s u m o f 3 co n sec u t i v e e v e n n u mb ers i s 403. Wha t i s t h e l a r g es t o f t h e n u mb ers ?

The largest number : 136 \frac{1}{3}

解答ステップ

Represent the numbers with

x

First number : x

Consecutive number 1 : x + 2

Consecutive number 2 : x + 4

A.T.Q.:

x + x + 2 + x + 4 = 403

解く

x + x + 2 + x + 4 = 403 : x = \frac{397}{3}

x + 2 = \frac{397}{3} + 2 = \frac{403}{3}

x + 4 = \frac{397}{3} + 4 = \frac{409}{3}

仮分数を帯分数に変換する:

\frac{397}{3} = 132 \frac{1}{3}

仮分数を帯分数に変換する:

\frac{403}{3} = 134 \frac{1}{3}

仮分数を帯分数に変換する:

\frac{409}{3} = 136 \frac{1}{3}

Select the largest solution:

136 \frac{1}{3}

The largest number : 136 \frac{1}{3}