展开 1/(s^n(s-8))

解答

展开

\frac{1}{s ^{n} ( s - 8 )}

\frac{1}{s ^{1 + n} - 8 s ^{n}}

求解步骤

\frac{1}{s ^{n} ( s - 8 )}

乘开

s^{n} (s - 8) : s^{1 + n} - 8 s^{n}

= \frac{1}{s ^{n + 1} - 8 s ^{n}}

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