erweitern-(2xy)/((x^2+1)(e^y+ln(x^2+1)))

Lösung

erweitern

- \frac{2 x y}{( x ^{2} + 1 ) ( e ^{y} + ln ( x ^{2} + 1 ) )}

- \frac{2 x y}{e ^{y} x ^{2} + x ^{2} ln ( x ^{2} + 1 ) + e ^{y} + ln ( x ^{2} + 1 )}

Schritte zur Lösung

- \frac{2 x y}{( x ^{2} + 1 ) ( e ^{y} + ln ( x ^{2} + 1 ) )}

Multipliziere aus

(x^{2} + 1) (e^{y} + ln (x^{2} + 1)) : e^{y} x^{2} + x^{2} ln (x^{2} + 1) + e^{y} + ln (x^{2} + 1)

= - \frac{2 x y}{e ^{y} x ^{2} + x ^{2} ln ( x ^{2} + 1 ) + ln ( x ^{2} + 1 ) + e ^{y}}

e x p an d \frac{1}{4} (\frac{2 - x}{3})^{3}

e x p an d (x - 2 a x + a)^{2}

s im pl i f y (\frac{x}{3} - \frac{2 y}{5}) (\frac{x}{3} + \frac{2 y}{5})

e x p an d \frac{x ^{2} - x - 1}{( x + 5 ) ( x ^{2} + 4 )}

e x p an d 4 (e^{- x} x - 2 e^{- x})