展開する-3^{1/3}(2x^2-3x+5+2x^{1/2}-4x^{3/2})

解

展開する

- 3^{\frac{1}{3}} (2 x^{2} - 3 x + 5 + 2 x^{\frac{1}{2}} - 4 x^{\frac{3}{2}})

- 3^{\frac{1}{3}} \cdot 2 x^{2} + 3^{\frac{1}{3}} \cdot 3 x - 3^{\frac{1}{3}} \cdot 5 - 3^{\frac{1}{3}} \cdot 2 x^{\frac{1}{2}} + 3^{\frac{1}{3}} \cdot 4 x^{\frac{3}{2}}

解答ステップ

- 3^{\frac{1}{3}} (2 x^{2} - 3 x + 5 + 2 x^{\frac{1}{2}} - 4 x^{\frac{3}{2}})

括弧を分配する

= - 3^{\frac{1}{3}} \cdot 2 x^{2} - 3^{\frac{1}{3}} (- 3 x) - 3^{\frac{1}{3}} \cdot 5 - 3^{\frac{1}{3}} \cdot 2 x^{\frac{1}{2}} - 3^{\frac{1}{3}} (- 4 x^{\frac{3}{2}})

簡素化

- 3^{\frac{1}{3}} \cdot 2 x^{2} - 3^{\frac{1}{3}} (- 3 x) - 3^{\frac{1}{3}} \cdot 5 - 3^{\frac{1}{3}} \cdot 2 x^{\frac{1}{2}} - 3^{\frac{1}{3}} (- 4 x^{\frac{3}{2}}) : - 3^{\frac{1}{3}} \cdot 2 x^{2} + 3^{\frac{1}{3}} \cdot 3 x - 3^{\frac{1}{3}} \cdot 5 - 3^{\frac{1}{3}} \cdot 2 x^{\frac{1}{2}} + 3^{\frac{1}{3}} \cdot 4 x^{\frac{3}{2}}

= - 3^{\frac{1}{3}} \cdot 2 x^{2} + 3^{\frac{1}{3}} \cdot 3 x - 3^{\frac{1}{3}} \cdot 5 - 3^{\frac{1}{3}} \cdot 2 x^{\frac{1}{2}} + 3^{\frac{1}{3}} \cdot 4 x^{\frac{3}{2}}