erweitern (3sin^2(θ))(1+sin^2(θ))

Lösung

erweitern

(3 sin^{2} (θ)) (1 + sin^{2} (θ))

3 sin^{2} (θ) + 3 sin^{4} (θ)

Schritte zur Lösung

(3 sin^{2} (θ)) (1 + sin^{2} (θ))

Wende das Distributivgesetz an:

a (b + c) = ab + a c

(3 sin^{2} (θ)) (1 + sin^{2} (θ)) = 3 sin^{2} (θ) \cdot 1 + 3 sin^{2} (θ) sin^{2} (θ)

= 3 sin^{2} (θ) \cdot 1 + 3 sin^{2} (θ) sin^{2} (θ)

Vereinfache

3 sin^{2} (θ) \cdot 1 + 3 sin^{2} (θ) sin^{2} (θ) : 3 sin^{2} (θ) + 3 sin^{4} (θ)

= 3 sin^{2} (θ) + 3 sin^{4} (θ)

e x p an d 3 (ln (- 1) + 1)

e x p an d (\frac{( n + 1 ) ( n + 2 )}{2})^{2}

e x p an d x^{\frac{1}{2}} (x^{\frac{3}{2}} - 4) (x^{\frac{1}{2}} + 4)

e x p an d (1 - ln (x)) d y

e x p an d (- \frac{1}{23 , 2 + 0 , 9 K}) \cdot (- 0.9 K^{2} + 53.6 K - 793.6)