What is (r-1/2)(r+3/4) ?

The solution to (r-1/2)(r+3/4) is ((2r-1)(4r+3))/8

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simplify (r-1/2)(r+3/4)

simplify

(r - \frac{1}{2}) (r + \frac{3}{4})

\frac{( 2 r - 1 ) ( 4 r + 3 )}{8}

Solution steps

(r - \frac{1}{2}) (r + \frac{3}{4})

Simplify

r - \frac{1}{2} : \frac{2 r - 1}{2}

= \frac{2 r - 1}{2} (r + \frac{3}{4})

Apply the fraction rule:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{( 2 r - 1 ) ( r + \frac{3}{4} )}{2}

Simplify

(2 r - 1) (r + \frac{3}{4}) : \frac{( 2 r - 1 ) ( r \cdot 4 + 3 )}{4}

= \frac{\frac{( 2 r - 1 ) ( r \cdot 4 + 3 )}{4}}{2}

Apply the fraction rule:

\frac{\frac{a}{b}}{c} = \frac{a}{b \cdot c}

= \frac{( 2 r - 1 ) ( r \cdot 4 + 3 )}{4 \cdot 2}

Multiply the numbers:

4 \cdot 2 = 8

= \frac{( 2 r - 1 ) ( r \cdot 4 + 3 )}{8}

= \frac{( 2 r - 1 ) ( 4 r + 3 )}{8}

(x + Δ)^{4}

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6 (12 + 7)

\frac{s + 1}{s ^{2} ( s ^{2} - 2 s + 5 )}

x^{4} 4 - x (e^{k} - e^{- x})