(3z}{1-i}+\frac{2z)/i = 6/(4+i)

解答

\frac{3 z}{1 - i} + \frac{2 z}{i} = \frac{6}{4 + i}

z = \frac{78}{85} + i \frac{6}{85}

求解步骤

\frac{3 z}{1 - i} + \frac{2 z}{i} = \frac{6}{4 + i}

乘以最小公倍数

3 i (4 + i) z + 2 (1 - i) (4 + i) z = 6 i (1 - i)

展开

3 i (4 + i) z + 2 (1 - i) (4 + i) z : 6 i z + 7 z

展开

6 i (1 - i) : 6 + 6 i

6 i z + 7 z = 6 + 6 i

分解

6 i z + 7 z : (6 i + 7) z

(6 i + 7) z = 6 + 6 i

两边除以

6 i + 7

z = \frac{78}{85} + i \frac{6}{85}

s im pl i f y \frac{6 n + 6}{n + 9} \cdot \frac{n ^{2} + 6 n - 27}{6 n + 6}

2 - 3 (x + 5) = 5 x - 13

s im pl i f y 3 \frac{1}{216}

\frac{2 x - 7}{4} \leq \frac{1}{5}

s im pl i f y (\frac{1}{4 ab})^{- 2}