展开 1/(((s^2+1)(s-3)(s-6)))

解答

展开

\frac{1}{( ( s ^{2} + 1 ) ( s - 3 ) ( s - 6 ) )}

\frac{1}{s ^{4} - 9 s ^{3} + 19 s ^{2} - 9 s + 18}

求解步骤

\frac{1}{( s ^{2} + 1 ) ( s - 3 ) ( s - 6 )}

乘开

(s^{2} + 1) (s - 3) (s - 6) : s^{4} - 9 s^{3} + 19 s^{2} - 9 s + 18

= \frac{1}{s ^{4} - 9 s ^{3} + 19 s ^{2} - 9 s + 18}

e x p an d (n + 1) (\frac{n}{2}) (n + 1)

e x p an d (s + p_{o}) (s + p_{1}) (s + p_{2})

e x p an d (x - y) \frac{d}{d y} (x y + 2)

e x p an d \frac{2 ( 2 + 10 )}{3}

s im pl i f y (\frac{x}{2} - \frac{3}{4}) (\frac{x}{2} + \frac{3}{4})