vereinfachen (1+i+t)^2

Lösung

vereinfachen

(1 + i + t)^{2}

(t^{2} + 2 t) + (2 + 2 t) i

Schritte zur Lösung

(1 + i + t)^{2}

Wende Exponentenregel an:

a^{b + c} = a^{b} \cdot a^{c}

(1 + i + t)^{2} = (1 + i + t) (1 + i + t)

= (1 + i + t) (1 + i + t)

Setze Klammern

= 1 \cdot 1 + 1 i + 1 \cdot t + i 1 + ii + i t + t \cdot 1 + t i + tt

Vereinfache

1 \cdot 1 + 1 i + 1 \cdot t + i 1 + ii + i t + t \cdot 1 + t i + tt : 2 i + t^{2} + 2 t + 2 t i

= 2 i + t^{2} + 2 t + 2 t i

Rewrite in standard complex form:

(t^{2} + 2 t) + (2 + 2 t) i

= (t^{2} + 2 t) + (2 + 2 t) i

e x p an d 2 (2 x - 3 = x + 2)

e x p an d \frac{2 s ^{3} - 5 s ^{2} + 8 s - 14}{( s ^{2} + 4 ) ( s - 1 ) ( s + 1 )}

e x p an d (sec (θ) + tan (θ)) cos (θ)

e x p an d \frac{( x + 2 ) ^{3} ( 9 x - 2 )}{12}

e x p an d \frac{( 4 x + 12 ) ^{2}}{4} + \frac{( y - 4 ) ^{2}}{4}