erweitern (4v^2-vsin(θ))^2

Lösung

erweitern

(4 v^{2} - v sin (θ))^{2}

16 v^{4} - 8 v^{3} sin (θ) + v^{2} sin^{2} (θ)

Schritte zur Lösung

(4 v^{2} - v sin (θ))^{2}

Wende Formel für perfekte quadratische Gleichungen an:

(a - b)^{2} = a^{2} - 2 ab + b^{2}

(4 v^{2} - v sin (θ))^{2} = (4 v^{2})^{2} - 2 \cdot 4 v^{2} v sin (θ) + (v sin (θ))^{2}

= (4 v^{2})^{2} - 2 \cdot 4 v^{2} v sin (θ) + (v sin (θ))^{2}

Vereinfache

(4 v^{2})^{2} - 2 \cdot 4 v^{2} v sin (θ) + (v sin (θ))^{2} : 16 v^{4} - 8 v^{3} sin (θ) + v^{2} sin^{2} (θ)

= 16 v^{4} - 8 v^{3} sin (θ) + v^{2} sin^{2} (θ)

e x p an d (4 x y + 2 x^{2} y) + (2 x^{2} + 3 y^{2}) y^{'} (x)

e x p an d x^{3} \cdot e^{3 x^{2}} (2 x + 3)

e x p an d 6 (- e^{3 x} (2 sin (2 x) - 3 cos (2 x)))

e x p an d (sec (x) + tan (x))^{3} (sec (x) - tan (x))^{4}

s im pl i f y ((cos (θ) + i sin (θ)))^{3}