展開する (2(h+2x))/((x+3)(x-3)(h+x+3)(h+x-3))

解

展開する

\frac{2 ( h + 2 x )}{( x + 3 ) ( x - 3 ) ( h + x + 3 ) ( h + x - 3 )}

\frac{2 h + 4 x}{x ^{4} + 2 h x ^{3} + h ^{2} x ^{2} - 18 x ^{2} - 18 h x - 9 h ^{2} + 81}

解答ステップ

\frac{2 ( h + 2 x )}{( x + 3 ) ( x - 3 ) ( h + x + 3 ) ( h + x - 3 )}

拡張

(x + 3) (x - 3) (h + x + 3) (h + x - 3) : x^{4} + 2 h x^{3} + h^{2} x^{2} - 18 x^{2} - 18 h x - 9 h^{2} + 81

= \frac{2 ( h + 2 x )}{x ^{4} + 2 h x ^{3} + h ^{2} x ^{2} - 18 x ^{2} - 18 h x - 9 h ^{2} + 81}

拡張

2 (h + 2 x) : 2 h + 4 x

= \frac{2 h + 4 x}{x ^{4} + 2 h x ^{3} + h ^{2} x ^{2} - 18 x ^{2} - 18 h x - 9 h ^{2} + 81}