展开 (x-1)ln(5)

解答

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(x - 1) ln (5)

ln (5) x - ln (5)

求解步骤

(x - 1) ln (5)

= ln (5) (x - 1)

使用分配律:

a (b - c) = ab - a c

a = ln (5), b = x, c = 1

= ln (5) x - ln (5) \cdot 1

= ln (5) x - 1 \cdot ln (5)

乘以:

1 \cdot ln (5) = ln (5)

= ln (5) x - ln (5)

e x p an d - \frac{y}{( x + 2 ) ^{2}}

e x p an d \frac{5 ( 3 + 3909 )}{6}

s im pl i f y (1 - e^{i x}) (1 - e^{- i x})

e x p an d \frac{36 ( - e ^{5 π} + 1 )}{725 e ^{5 π}}

e x p an d \frac{2 \cdot ( n + 1 + n \cdot 3 ^{n} + 3 ^{n} )}{n + 3 ^{n + 1}}