化简 2(sqrt(2)+1)

解答

化简

2 (2 + 1)

22 + 2

十进制

4.82842 \dots

求解步骤

2 (2 + 1)

使用分配律:

a (b + c) = ab + a c

2 (2 + 1) = 22 + 2 \cdot 1

= 22 + 2 \cdot 1

数字相乘:

2 \cdot 1 = 2

= 22 + 2

e x p an d (x e^{\frac{x}{2}} - 2 e^{\frac{x}{2}}) e^{x}

e x p an d \frac{( s \cdot ( s + 0.5 ) \cdot ( s + 1 ) \cdot ( s ^{2} + 0.4 s + 4 ) )}{s + 4}

e x p an d cos (x) (cos (y) - 1) - sin (x) sin (y)

e x p an d x^{2} \cdot sin (u s) (x + y^{2})

s im pl i f y (\frac{3}{2 x ^{3}} - 6 y) (\frac{3}{2 x ^{3}} + 6 y)