What is log_{b}((64)/(sqrt(x+1))) ?

The solution to log_{b}((64)/(sqrt(x+1))) is 6log_{b}(2)-log_{b}(sqrt(x+1))

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

simplify log_{b}((64)/(sqrt(x+1)))

simplify

lo g_{b} (\frac{64}{x + 1})

6 lo g_{b} (2) - lo g_{b} (x + 1)

Solution steps

lo g_{b} (\frac{64}{x + 1})

Apply log rule:

lo g_{a} (\frac{x}{y}) = lo g_{a} (x) - lo g_{a} (y)

lo g_{b} (\frac{64}{x + 1}) = lo g_{b} (64) - lo g_{b} (x + 1)

= lo g_{b} (64) - lo g_{b} (x + 1)

Simplify

lo g_{b} (64) : 6 lo g_{b} (2)

= 6 lo g_{b} (2) - lo g_{b} (x + 1)

3 lo g_{b} (m) - lo g_{b} (n)

\frac{1}{4} lo g_{b} (x) + 3 lo g_{b} (y) - 2 lo g_{b} (x)

2 ln (2 e)

2 ln (8) + 5 ln (z)

What is log_{b}((64)/(sqrt(x+1))) ?
The solution to log_{b}((64)/(sqrt(x+1))) is 6log_{b}(2)-log_{b}(sqrt(x+1))