What are the solutions to the equation -0.5x^2+12x+10=-4x+97.5 ?

The solutions to the equation -0.5x^2+12x+10=-4x+97.5 are x=7,x=25

Find the zeros of -0.5x^2+12x+10=-4x+97.5

The zeros of -0.5x^2+12x+10=-4x+97.5 are x=7,x=25

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- 0.5 x^{2} + 12 x + 10 = - 4 x + 97.5

x = 7, x = 25

Solution steps

- 0.5 x^{2} + 12 x + 10 = - 4 x + 97.5

Multiply both sides by

10

- 5 x^{2} + 120 x + 100 = - 40 x + 975

Move

975

to the left side

- 5 x^{2} + 120 x - 875 = - 40 x

Move

40 x

to the left side

- 5 x^{2} + 160 x - 875 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 160 \pm 16 0 ^{2} - 4 ( - 5 ) ( - 875 )}{2 ( - 5 )}

16 0^{2} - 4 (- 5) (- 875) = 90

x_{1, 2} = \frac{- 160 \pm 90}{2 ( - 5 )}

Separate the solutions

x_{1} = \frac{- 160 + 90}{2 ( - 5 )}, x_{2} = \frac{- 160 - 90}{2 ( - 5 )}

x = \frac{- 160 + 90}{2 ( - 5 )} : 7

x = \frac{- 160 - 90}{2 ( - 5 )} : 25

The solutions to the quadratic equation are:

x = 7, x = 25

9 x^{2} - 39 = 0

- 5 p^{2} + 8 p - 8 = - 6 p^{2}

12 x^{2} - 24 x + 8 = 0

y^{2} + 9 y + 18 = 0

x, 9 x^{2} + 4 x y + 6 y^{2} + 12 x + 36 y + 44 = 0

What are the solutions to the equation -0.5x^2+12x+10=-4x+97.5 ?
The solutions to the equation -0.5x^2+12x+10=-4x+97.5 are x=7,x=25
Find the zeros of -0.5x^2+12x+10=-4x+97.5
The zeros of -0.5x^2+12x+10=-4x+97.5 are x=7,x=25